Answer:
14.15 g of Ethyl Butyrate
Solution:
The Balance Chemical Equation is as follow;
Butanoic Acid + Ethanol → Ethyl Butyrate + Water
Molar Mass of Butanoic Acid = 88.11 g.mol⁻¹
Molar Mass of Ethanol = 46.07 g.mol⁻¹
Molar Mass of Ethyl Butyrate = 116.16 g.mol⁻¹
Molar Mass of Water = 18.01 g.mol⁻¹
Step 1: Calculating Theoretical Yield:
According to Equation,
88.11 g (1 mol) Butanoic Acid forms = 116.16 g (1 mol) Ethyl Butyrate
So,
13.58 g Butanoic Acid will form = X g of Ethyl Butyrate
Solving for X,
X = (13.58 g × 116.16 g) ÷ 88.11 g
X = 17.90 g
Theoretical Yield = 17.90 g
Step 2: Calculating Actual Yield:
As,
%age Yield = Actual Yield ÷ Theoretical Yield × 100
Solving for Actual Yield,
Actual Yield = %age Yield × Theoretical Yield ÷ 100
Putting Values,
Actual Yield = 79.1 × 17.90 ÷ 100
Actual Yield = 14.15 g of Ethyl Butyrate
