I would say the atoms in the fork are moving faster. 0 degrees Fahrenheit is -17.7778 in Celsius while 0 degrees in Celsius is equal to 32 degrees in Fahrenheit.
False
Explanation:
because every problem of a mankind has a solution
Answer:
1837.89 Lt
Explanation:
The chemical reaction for this situation is:
NaHCO₃ + HCl → NaCL + H₂O + CO₂ ₍g₎
Where the mola mass we need are:
M NaHCO₃ = 84 g/mol
M CO₂ = 44 g/mol
As we have 6.00 Kg of sodium bicarbonate, then:
6 Kg NaHCO₃ = 71.43 moles of NaHCO₃
Due the stoichiometry of this chemaicl reaction:
1 mol NaHCO₃ = 1 mol CO₂
71.43 moles NaHCO₃ = 71.43 moles CO₂
And considering that CO₂ is an ideal gas, we can use the following formula:
PV=nRT
V = (nRT)/P
n = 71.43 mol
R = 0.083 Ltxatm(molxK)
T = 37°C = 310 K
P = 1 atm
So: V = (71.43x0.083x310)/1
V CO₂ = 1837.89 Lt
Answer:
Explanation:
Let's consider the following chemical equilibrium:
CaCO₃(s) ⇄ CaO(s) + CO₂(g)
Given the pressure equilibrium constant Kp = pCO₂
We can calculate the concentration equilibrium constant (Kc) using the following expression.
where,
R is the ideal gas constant
T is the absolute temperature
Δn(g) = moles of gaseous products - moles of gaseous reactants = 1 - 0 = 1
The expression for this reaction is:
Answer:
There will be 525.2 grams of K3N produced
Explanation:
Step 1: Data given
Number of moles of potassium oxide ( K2O) = 6 moles
Magnesium nitride (Mg3N) = in excess
Molar mass of K3N = 131.3 g/mol
Step 2: The balanced equation
Mg3N2 + 3K2O → 3MgO + 2K3N
Step 3: Calculate moles of K3N
The limiting reactant is K2O.
For 1 mol Mg3N2 consumed, we need 3 moles of K2O to produce 3 moles of MgO and 2 moles of K3N
For 6 moles K2O we'll have 2/3 * 6 = 4 moles of K3N
Step 4: Calculate mass of K3N
Mass of K3N = moles K3N * molar mass K3N
Mass of K3N = 4 moles * 131.3 g/mol
Mass of K3N = 525.2 grams
There will be 525.2 grams of K3N produced
