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Inessa05 [86]
2 years ago
10

A student wants to prepare 250.0 mL of 0.10 M NaCl solution. Which procedure is most appropriate? (formula Molar Mass of NaCl =

58.4 g/mol)
A) Add 5.84 g of NaCl to 250. mL of H2O
B) Add 1.46 g of NaCl to 250. mL of H2O
C) Dissolve 5.84 g of NaCl in 50 mL of H2O and dilute to 250. mL
D) Dissolve 1.46 g of NaCl in 50 mL of H2O and dilute to 250. mL
Chemistry
1 answer:
Anvisha [2.4K]2 years ago
3 0

The correct answer is option B, that is, add 1.46 grams of NaCl to 250 milliliters of H₂O.

First there is a need to find the moles of NaCl in 250 ml of 0.10 M NaCl,

Moles of NaCl = molarity × volume = 0.10 M × (250/1000L) = 0.025 mol

The corresponding mass of NaCl is,

Mass of NaCl = moles × molar mass = 0.025 mol × 58.5 g/mol = 1.46 g

Thus, there is a need to dissolve 1.46 grams of NaCl solid into 50 ml of H₂O and dilute to 250 ml.

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Mg(OH)2 + 2 HBr à MgBr2 + 2 H2O
AnnyKZ [126]

Explanation:

The balanced equation of the reaction is given as;

Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)

1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?

From the reaction;

2 mol of HBr produces 1 mol of  MgBr2

Converting to masses using;

Mass = Number of moles * Molar mass

Molar mass of HBr = 80.91 g/mol

Molar mass of MgBr2 = 184.113 g/mol

This means;

(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2

18.3g would produce x

161.82 = 184.113

18.3 = x

x = (184.113 * 18.3 ) / 161.82 = 20.8 g

2. How many moles of H2O will be produced from 18.3 grams of HBr?

Converting the mass to mol;

Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol

From the reaction;

2 mol of HBr produces 2 mol of H2O

0.226 mol would produce x

2 =2

0.226 = x

x = 0.226 * 2 / 2 = 0.226 mol

3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?

From the reaction;

2 mol of HBr reacts with 1 mol of Mg(OH)2

18.3g of HBr =  0.226 mol

2 = 1

0.226 = x

x = 0.226 * 1 /2

x = 0.113 mol

5 0
2 years ago
Which of the following statements are true of acids and bases?
gtnhenbr [62]
A. Acids increase the number of OH- ions in a solution. FALSE
B. Bases increase the number of OH- ions in a solution. TRUE
C. Acids increase the number of H+ ions in a solution. TRUE
D. Bases increase the number of H+ ions in a solution. FALSE
8 0
3 years ago
WILL GIVE BRAINLIEST!Which statement best describes electrolytic and voltaic cells?
Jlenok [28]

Answer:

the last answer is right.

3 0
3 years ago
Iron is a metal. The structure of iron is described as a lattice of positive ions in a sea of
KATRIN_1 [288]

Answer: 1and 4

Explanation: iron is an element not an alloy. An ionic lattice is not bonded covalently.

6 0
2 years ago
Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels. The heat of combustion of cyclobutane, C4H8
Gennadij [26K]

Answer:

1. C4H8 + 6O2  -----> 4CO2 + 4H20

2. 3836.77 kcal

Explanation:

1. Balanced equation for the complete combustion of cyclobutane:

C4H8 + 6O2  -----> 4CO2 + 4H20

2. Heat of combustion of cyclobutane = 650.3 kcal/mol

    Molecular weight of cyclobutane, C4H8 = 56.1 g/mol

   Mole of C4H8 : mass of cyclobutane/Molecular weight of cyclobutane

  Mole of C4H8 = 331/56.1 = 5.9 mol

Energy released during combustion =  5.9 mol × 650.3 kcal/mol = 3836.77kcal

Therefore the energythat  is released during the complete combustion of 331 grams of cyclobutane is 3836.77kcal

8 0
2 years ago
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