Answer:
The correct answer is 10.939 mol ≅ 10.94 mol
Explanation:
According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).
For the initial gas (1), we have:
n₁= 1.59 mol
V₁= 641 mL= 0.641 L
For the final gas (2), we have:
V₂: 4.41 L
The relation between 1 and 2 is given by:
n₁/V₁ = n₂/V₂
We calculate n₂ as follows:
n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol
Answer:
not capable of being imagined or grasped mentally; unbelievable.
Explanation:
not capable of being imagined or grasped mentally; unbelievable.
The standard enthalpy of formation (Δ
) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.
Standard enthalpies (Δ) of formation for given reaction is 978.3 kJ
<h3>
What is Standard enthalpies of formation?</h3>
The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.
Given reaction ;
To Find : Δ
Δ = ∑np Δ (products) – ∑np Δ (reactants)
Δ = [1(Δ 
) + 4(Δ 
)] – [1(Δ 
) + 4(Δ 
)]
Δ = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]
Δ = [4(-241.8)] – [1(+9.16)] = 978.3 kJ
Learn more about Enthalpy here ;
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Answer:
Two
Explanation:
In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products.
