Answer:
w = 0.00098 N
Explanation:
Given data:
Acceleration = 9.80 m/s²
Mass of honey = 0.0001 Kg
weight = ?
Solution:
Formula:
w = mg
w = weight
m = mass
g = acceleration due to gravity
Now we will put the values in formula:
w = 0.0001 Kg × 9.80 m/s²
w = 0.00098 N
<u>Answer:</u> The net ionic equation is written below.
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of ammonium carbonate and lead (II) nitrate is given as:
Ionic form of the above equation follows:
As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
Hence, the net ionic equation is written above.
Answer:
See below.
Explanation:
1. The water here is the solvent, and the 'sugar and fruit specific chemicals' are considered the solute. That is as the solute is the component dissolved in the solvent.
2. The collision theory states that the greater the collisions, the greater the rate of reaction. When powdered sugar is placed in the water (solvent) it occupies more surface area, resulting in more collisions that speed up the rate of reaction, compared to a cube of sugar - that occupies less surface area. Therefore, the powdered sugar dissolved faster.
3. Molarity describes the number of moles of a substance per unit of volume. The standard unit of volume is liter, giving you the standard units (mol/l). Molality describes the number of moles per unit of mass, typically kilograms (mol/kg).
The concentration of a solution can be given in moles of solute dissolved per kilogram of solvent for molality, and moles of solute dissolved in liters of solvent for molarity. Molality is generally used for concentration.
To calculate percent errorsubtract the accepted value from the experimental value.Take the absolute value of step 1.Divide that answer by the accepted value.Multiply that answer by 100
so% error = [|(10.085 g/ 10 ml) - 0.9975| / 0.9975] x 100
% error = 1.1 %