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NemiM [27]
3 years ago
11

You are in Paris, 60 m up in the Eiffel Tower. If you throw a euro downward at a velocity of 2.0 m/s, how long would it take the

euro to hit the ground? Neglect air resistance.
Physics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

t = 3.29 seconds

Explanation:

It is given that,

Height of the Eiffel tower is 60 m

Initial speed of a euro, u = 2 m/s

It will move under the action of gravity in the downward direction. Firstly, we can find the final velocity as follows :

v^2-u^2=2ad\\\\v=\sqrt{u^2+2ad} \\\\v=\sqrt{(2)^2+2\times 9.81\times 60} \\\\v=34.36\ m/s

Let t is the time taken by the euro to hit the ground. It can be calculated as :

v=u+at\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{34.36-2}{9.81}\\\\t=3.29\ s

Hence, it will take 3.29 seconds to hit the ground.

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A student of weight 659 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude
Misha Larkins [42]

Answer:

a) The student feel light

b) Nbottom = 758 N

c) N'top= 236 N

d) N'bottom= 1055 N

Explanation:

a) W= 659N , Ntop= 560N

W > Ntop ---> Student feel less weight

b)   Top:

∑F= W - Ntop = m.v²/R

m.v²/R = 659N - 560 N = 99 N

Bottom:

∑F= Nbottom- W = m.v²/R

Nbottom= W + m.v²/R = 659N + 99 N = 758N

c) W= 659 N , Ntop= 560 N , v'=2.v

N'top= ?

∑F= W - N'top = m.v'²/R

N'top= W - 4.m.v²/R

N'top = 659 N - 4. 99 N = 263 N

d)   N'bottom = ?

∑Fbottom= N'bottom- W = m.v'²/R

N'bottom = W + 4.m.v²/R = 659 N + 4. 99 N = 1055 N

4 0
2 years ago
Which sentence uses a verb incorrectly?
Burka [1]

Answer:

The answer is B).

Explanation:

The correct way to write this sentence is: After I woke up this morning, I got me a tall glass of orange juice.

5 0
3 years ago
A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction
Elis [28]

Answer:

(a) 25 m

(b) 75 m

Explanation:

Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.

So, the speed of the jogger,

v=\frac{10}{2}=5m/s\;\cdots(i)

Let d be the distance covered by him in time, t s.

As distance=(speed) x (time)

So, d=vt

From equation (i)

\Rightarrow d=5t\;\cdots(ii)

As the jogger starts from origin, so, the distance, d, also represents the position of the jogger at the time t s.

The position-time graph has been shown.

(a) From equation (ii), for t=5.0 s

d=5\times 5=25 m

So, the jogger is at a distance of 25 m from the origin.

(b) Similarly, for t=15.0 s

d=5\times 15=75 m

So, the jogger is at a distance of 75 m from the origin.

8 0
2 years ago
What distance does electromagnetic radiation travel in 55.0 μs ?
Komok [63]
Electromagnetic radiation is an energy that is known as light. so electromagnetic radiation will have the same speed as the speed of light which is 3 x 10^8 m/s. so the distance it travel at 55 x 10^-6 s is:
D = ( 3 x 10^8 m/s ) (  55 x 10^-6 s )
D = 16500 m
4 0
3 years ago
What are close-toed shoes least likely to provide protection against?
Dennis_Churaev [7]
Hydrogen gas is harmless to your feet so since you don’t need protection against it that seems the best answer.
8 0
2 years ago
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