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Vladimir [108]
3 years ago
11

What velocity must a car with a mass of 1110 kg have in order to have the same momentum as a 2280 kg pickup truck traveling at 2

4 m/s to the east? Answer in units of m/s.
Physics
1 answer:
shutvik [7]3 years ago
6 0

Answer:

49.3 m/s

Explanation:

The momentum is defined as the product of the object velocity and its mass.

So the momentum of the truck is

P_t = 2280 * 24 = 54720 kgm/s

For the car to have the same momentum, its speed must be

v_c = P_t/m_c = 54720 / 1110 = 49.3 m/s

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How does the circuit change when the wire is added? a closed circuit occurs and makes all bulbs turn off. an open circuit occurs
Vitek1552 [10]

The circuit change when a wire is added is, an open circuit occurs and makes all bulbs turn off.

<h3>What is a closed circuit?</h3>

A closed circuit is a type of circuit connection in which the wire connection is complete and current flow occurs, turning the light bulbs on in the process.

<h3>What is an open circuit?</h3>

An open circuit is a type of circuit connection in which the wire connection is incomplete and current cannot flow, turning off the light bulbs.

Thus, the circuit change when the wire is added is, an open circuit occurs and makes all bulbs turn off.

Learn more about open circuit here: brainly.com/question/20351910

#SPJ4

3 0
2 years ago
For a vehicle to negotiate a banked curve in poor weather conditions, where the force of friction f = 0, for a given velocity v
djverab [1.8K]

Answer:

R=240m

Explanation:

From the question we are told that:

Velocity v=25m/s

Force of friction f = 0

Angle \theta=15

Generally the equation for  Radius of curvature is mathematically given by

R=frac{v^2}{tan\theta *g}

R=frac{25^2}{tan 15 *9.81}

R=240m

7 0
3 years ago
HELP PLEASE 20 ;OINTS
77julia77 [94]
I’m pretty sure it’s C.
7 0
3 years ago
Which one of the following is a decomposition reaction?
horsena [70]
It would be A because Decomposition is when a substance breaks down into two. 
8 0
3 years ago
Read 2 more answers
We have three identical metallic spheres A, B, C. Initially sphere A is charged with charge Q, while B and C are neutral. First,
larisa [96]

Answer:

The final charges of each sphere are:   q_A = 3/8 Q , q_B = 3/8 Q ,               q_C = 3/4 Q

Explanation:

This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.

Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point

                q_A = Q / 2

                q_B = Q / 2

Now sphere A touches sphere C, ending with half the charge

                q_A = ½ (Q / 2) = ¼ Q

                q_B = ¼ Q

Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge

                  q = Q / 4 + Q / 2 = ¾ Q

This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q

                  q_A = 3/8 Q

                  q_B = 3/8 Q

The final charges of each sphere are:

                q_A = 3/8 Q

                q_B = 3/8 Q

                q_C = 3/4 Q

7 0
3 years ago
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