Answer:
369.84 W
Explanation:
= Mass flow rate = 10.62 kg/s
v = Velocity of wind = 8 m/s
Power is given by
The power supplied is 339.84 W
If 30 W of this power is wasted that means 339.84+30 = 369.84 W is required
Answer:
a) 12.56 rad per minute
b)62.8 inches per minute
Explanation:
Given:
- Radius of the blades, R=5 inches
- Frequency of the blades, f=2 revolutions per minute
a)
Let be the angular velocity of the blade which is given by
b)
Let v be the linear speed of the tip of the blade which is given by
Hence we have calculated the angular velocity and linear speed.
Answer:
Absolute magnitude
Explanation:
The brightness a star would have if it were at 10 pc from Earth is called Absolute magnitude.
Answer:
The orbital speed of the satellite around the earth in other to remain in perfect circular orbit in given as:
v = sqrt[(Ge*M)/R],
where Ge is the gravitational constant (Ge = 6.673 x 10^-11N/m2/kg2), M is the mass of the earth(m = 5.98 x 10^24kg), and R is the radius of the earth (R = 6.47 x 10^6m)
v = SQRT [ (6.673 x 10^-11 N m2/kg2) • (5.98 x 10^24 kg) / (6.47 x 10^6 m) ]
v = 7.85 x 10^3 m/s
Explanation:
For a satelite in a low altitude orbit around the Earth, the gravitational force is the only force acting of the said satellite keeping it is a circular orbit. To keep this satellite in perfect circular orbit, it must be moving in at a certain speed, which is dependent on the earth mass and radius. This speed can be evaluated from the expression of centripetal force(F = mv2/r). The centripetal force Fc on the satellite is equal to the gravitational force on the satellite from the earth(Fe). That is, (Ge*M*m)/R2 = (m*v2)/R, where M is mass of the earth, and m is the mass of the satellite. making v the subject of the formula, the equation become v = sqrt[(Ge*M)/R].
Answer:
I think the acceleration is 12m/s