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Tresset [83]
3 years ago
13

How is Venus similar to Earth?

Physics
2 answers:
Oksanka [162]3 years ago
6 0

Answer:

D: Both have a solid inner core and a liquid outer core.

Explanation:

hoa [83]3 years ago
5 0

Answer: D

Explanation: I have my answers VS. Go0gle answers (go0gle answers are pics)

(A) Both have the same day length. Well, Venus doesn't havve the same amount of days. (I already know off the top of my head, but I still searched it up)

(B) Both rotate in the same direction. In school (before Virus) they would always show diagrams of the planets on the projector and Venus doesn't rotate

(C) Both have ample water. No. Venus doesn't have much water >_>

(D) Both have a solid inner core and a liquid outer core. Yesh. In my lessons (before), Venus has a solid inner core and liquid outer core.

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A 30%-efficient car engine accelerates the 1300 kg car from rest to 10 m/s . How much energy is transferred to the engine by bur
WITCHER [35]

Answer:

The Energy transferred to the engine by burning gasoline = <u>216.67 KJ</u>

Explanation:

The parameters given are:

The efficiency of the car engine, E = 30% = 0.3

Mass, m = 1300 kg

Initial velocity, u = 0, since the car is from rest

The final velocity, v = 10 m/s

Since the car was moving, we calculate its kinetic energy.

kinetic energy = ((1/2) (m) (v^2)

((1/2) (1300 kg) (10 m/s^2)

= 65,000 j

The Energy, Q transferred to the engine by burning gasoline in this case

= potential energy / The efficiency of the car engine, E

Q = 65,000 j / 0.3

= 216,666.66 J

Converting Joule to kilojoule

where 1KJ = 1000j

216,666.66 J = <u>216.67 KJ</u>

3 0
4 years ago
a 1020-hertz sound wave travels at 340 m/s in air with a wavelength of a) 30 m. b) 3 m. c) 0.333 m. d) 1 m. e) none of the above
eimsori [14]

The wavelength of the sound wave is equal to 0.333 m. Therefore, option (c) is correct.

<h3>What are frequency and wavelength?</h3>

The frequency of the wave can be defined as the number of oscillations that occur in one second and can be expressed in hertz. The wavelength can be defined as the distance between the two adjacent points of a wave such as two crests or troughs.

The relationship between frequency (ν), speed of sound waves (V), and  wavelength (λ):

V = νλ

Given, the frequency of the sound wave, ν = 10 Hz

The speed of the sound wave,V = 340 m/s

The wavelength of the sound waves can determine as follows

λ = V/ν = 340/1020 = 0.333 m.

Therefore, the wavelength of the sound wave is 0.333 m

Learn more about wavelength and frequency, here:

brainly.com/question/18651058

#SPJ1

5 0
1 year ago
What would happen if an automobile moving at a high speed suddenly comes to a stop? How does this relate to Newton's laws and wh
insens350 [35]
If an automobile moving at high speed suddenly comes to a stop, you would have a large change in momentum. This relates to Newton's second law in the form F = delta p / delta t, where p is momentum (mv).
You could lessen the effect of the sudden stop on the passengers by changing the average force exerted on them. If you look at Newton's second law again, you can see that given some delta p, you can decrease F by increasing delta t. What this means is that if you increase the length of time over which the change in momentum occurs, you can decrease the average force exerted to obtain that change in momentum. This is the reason why landing on a soft cushion is preferable to landing on a concrete surface. The cushion gives way to any object falling on it while still providing some resistance (you don't stop as abruptly), so while your change in momentum is the same in both cases, you have a larger delta t in the case of the cushion.
6 0
3 years ago
Why is it important to use constants in an experiment?
Firlakuza [10]
<span>In order for the results to be valid, the dependent variable can only be affected by the independent variable, so somethings need to be kept constant. The things that need to be kept constant are called  controlled variables.</span>
5 0
3 years ago
Find the intensity of electromagnetic radiation at the surface of the sun (radius r=R=6.96×105kmr=R=6.96×105km). Ignore any scat
alisha [4.7K]

Answer:

I = 4.46*10^{16}W/m^2.

Explanation:

Intensity I of the electromagnetic radiation is given by

I = \dfrac{P}{4\pi r^2},

where r is the distance from the EM source (the center of the sun, in our case), and P is the power output of the sun and it has the value

P = 3.9 *10^{26}W.

Since the radius of the sun in meters is r = 6.96*10^8km, the intensity I of the electromagnetic radiation at the surface of the sun is

I = \dfrac{3.9*10^{26}W}{4\pi (6.96*10^8m)^2}\\\\\boxed{ I = 4.46*10^{16}W/m^2}

The intensity of the electromagnetic radiation at the surface of the sun is I = 4.46*10^{16}W/m^2.

7 0
3 years ago
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