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Tresset [83]
3 years ago
13

How is Venus similar to Earth?

Physics
2 answers:
Oksanka [162]3 years ago
6 0

Answer:

D: Both have a solid inner core and a liquid outer core.

Explanation:

hoa [83]3 years ago
5 0

Answer: D

Explanation: I have my answers VS. Go0gle answers (go0gle answers are pics)

(A) Both have the same day length. Well, Venus doesn't havve the same amount of days. (I already know off the top of my head, but I still searched it up)

(B) Both rotate in the same direction. In school (before Virus) they would always show diagrams of the planets on the projector and Venus doesn't rotate

(C) Both have ample water. No. Venus doesn't have much water >_>

(D) Both have a solid inner core and a liquid outer core. Yesh. In my lessons (before), Venus has a solid inner core and liquid outer core.

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What is the charge of an object that has lost 25 electrons?
Wewaii [24]
A negative charge i guess

7 0
4 years ago
A celestial body has these properties:
vichka [17]
I think that would be the moon

"too small to clear objects that are in its orbital path" , which means that it probably not a planet.

hope this helps
4 0
3 years ago
Read 2 more answers
For a point charge, how does the potential vary with distance from the point charge, r?
mr_godi [17]

For a point charge, how does the potential vary with distance from the point charge, r?

a constant

b. r.

c. 1/r.

d. 1/r^2.

e. r^2.

Answer:

The  correct option is  C

Explanation:

Generally for a point charge the electric potential is mathematically represented as

    V  =  \frac{k  Q  }{r }

Here we can deduce that the electric potential varies inversely with the distance i.e

      V  \  \alpha \  \frac{1}{r}

So

   

3 0
3 years ago
1. Which direction will the box move in the diagram below? (1 point)
svetoff [14.1K]

I think it would'nt move at all but im not postive

6 0
4 years ago
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
tresset_1 [31]

Answer:

Explanation:

a. Given that:

m- mass of first & second piece, 3m-mass of 3rd piece,\bar v_1-velocity of first piece(-23\dot i \ m/s) and \bar v_2 as velocity of 2nd piece (-23\dot j \ m/s)

Let \bar v_3 be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

m\bar v_1 +m\bar v_2 +3m \bar v_3=0   #Dividing both sides by m, m\neq 0

\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)

#Plug the\bar v_1 ,\bar v_2  values:

\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)

#So the magnitude of the third piece is:

|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the x-axis), we find \angle \theta. The angle is obtained by getting the tan inverse as:

\theta=tan^-^1(\frac{23/3}{23/3})\\=45\textdegree

-The direction of the magnitude (angle relative to the x-axis) is 45°

6 0
3 years ago
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