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3 years ago

How is Venus similar to Earth?

Physics

2 answers:

Oksanka [162]3 years ago

6 0

Answer:

D: Both have a solid inner core and a liquid outer core.

Explanation:

hoa [83]3 years ago

5 0

Answer: D

Explanation: I have my answers VS. Go0gle answers (go0gle answers are pics)

(A) Both have the same day length. Well, Venus doesn't havve the same amount of days. (I already know off the top of my head, but I still searched it up)

(B) Both rotate in the same direction. In school (before Virus) they would always show diagrams of the planets on the projector and Venus doesn't rotate

(C) Both have ample water. No. Venus doesn't have much water >_>

(D) Both have a solid inner core and a liquid outer core. Yesh. In my lessons (before), Venus has a solid inner core and liquid outer core.

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A car travelling at 15 m/s comes to rest in a distance of 14 m when the brakes are applied.

stira [4]

Answer:

-8.04 m/s2

Explanation:

To find the answer to this, you have to use the 4th kinematic equation:

$v^{2} = v^{2}_{0} + 2ax$

You plug into the equation to get:

$0 = 15^{2} + 2a(14)$

solve for a to get

-8.04 m/s2

3 0

3 years ago

Using a refracting telescope, you observe the planet Mars when it is 2.11 × 10 11 m 2.11×1011 m from Earth. The diameter of the

Norma-Jean [14]

Answer:

y = 150 Km

Explanation:

given,

Distance of the planet Mars from earth D = 2.11 × 10¹¹ m

The diameter of the telescope's objective lens d = 0.949 m

The wavelength of light λ = 553 nm

= 553 x 10⁻⁹ m

resolution of the telescope = ?

$y = \dfrac{1.22\lambda\ D}{d}$

$y = \dfrac{1.22\times 553\times 10^{-9}\times 2.11 \times 10^{11}}{0.949}$

y = 150003 m

y = 150 Km

the minimum feature size is equal to y = 150 Km

8 0

3 years ago

What statement BEST describes a solid?

g100num [7]

C. Solids have a definite shape and definite volume.
is the correct one.

5 0

4 years ago

Read 2 more answers

BRAINLIEST. Agraph is probelow. The graph shows the speed of a car traveling east over a 12 second period. Based on the informat

gavmur [86]

Answer: Speeding up constantly

Explanation:

3 0

4 years ago

Read 2 more answers

One long wire carries a current of 30 A along the entire x axis. A second long wire carries a current of 40 A perpendicular to t

WINSTONCH [101]

Complete question is;

One long wire carries a current of 30 A along the entire x axis. A second long wire carries a current of 40 A perpendicular to the xy plane and passes through the point (0, 4, 0) m. What is the magnitude of the resulting magnetic field at the point y = 2.0 m on the y axis?

Answer:

B_net = 50 × 10^(-7) T

Explanation:

We are told that the 30 A wire lies on the x-plane while the 40 A wire is perpendicular to the xy plane and passes through the point (0,4,0).

This means that the second wire is 4 m in length on the positive y-axis.

Now, we are told to find the magnitude of the resulting magnetic field at the point y = 2.0 m on the y axis.

This means that the position we want to find is half the length of the second wire.

Thus, at this point the net magnetic field is given by;

B_net = √[(B1)² + (B2)²]

Where B1 is the magnetic field due to the first wire and B2 is the magnetic field due to the second wire.

Now, formula for magnetic field due to very long wire is;

B = (μ_o•I)/(2πR)

Thus;

B1 = (μ_o•I_1)/(2πR_1)

Also, B2 = (μ_o•I_2)/(2πR_2)

Now, putting the equation of B1 and B2 into the B_net equation, we have;

B_net = √[((μ_o•I_1)/(2πR_1))² + ((μ_o•I_2)/(2πR_2))²]

Now, factorizing out some common terms, we have;

B_net = (μ_o/2π)√[((I_1)/R_1))² + ((I_2)/R_2))²]

Now,

μ_o is a constant and has a value of 4π × 10^(−7) H/m

I_1 = 30 A

I_2 = 40 A

Now, as earlier stated, the point we are looking for is 2 metres each from wire 2 end and wire 1.

Thus;

R_1 = 2 m

R_2 = 2 m

So, let's calculate B_net.

B_net = ((4π × 10^(−7))/2π)√[(30/2)² + (40/2)²]

B_net = 50 × 10^(-7) T

5 0

3 years ago