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Nataliya [291]
3 years ago
7

A snail can move approximately 0.30 meters per minute.how many meters can the snail cover in 15 minutes?

Physics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

4.5 meters is your Answer goood luck please give 5 star

Explanation:

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An object slides down a frictionless inclined plane. At the bottom, it has a speed of 9.80 m/s. What is the vertical height of t
Papessa [141]

The vertical height of the given plane is 4.9 m.

The given parameters:

  • <em>speed of the object at the bottom of the ramp, v = 9.8 m/s</em>

The vertical height of the plane is calculated by applying principle of conservation of mechanical energy as follows;

P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{9.8 \times 9.8}{2 \times 9.8} \\\\h = 4.9 \ m

Thus, the vertical height of the given plane is 4.9 m.

Learn more about conservation of mechanical energy here: brainly.com/question/332163

7 0
3 years ago
Match each scenario to the form of energy it represents.
Pachacha [2.7K]
<span>Correct pairs:

a man jogging in the park --> motion energy (the energy is the kinetic energy of the man, moving with speed v)

a fully charged camera battery --> electric potential energy (the battery is fully charged, so it can deliver electrical energy when the camera is turned on)

a stove burner that’s turned on --> radiant energy (the stove burner emits energy by radiation)

an apple on a tree --> gravitational potential energy (when the apple is on the tree, it has gravitational potential energy equal to U=mgh, where m is the apple's mass and h its height from the ground)
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5 0
3 years ago
Basketball= What is the half of the court that is farthest from the offensive basket?
klasskru [66]
The answer would be half court I think
6 0
3 years ago
Two horizontal forces are exerted on a large crate. The first force is 317 N to the right. The second force is 173 N to the left
DENIUS [597]

Answer:

A. Refer to the figure.

B. The net force acting on the crate is

F_{net} = F_1 - F_2 = 317 - 173 = 144N

C. We should first find the acceleration of the crate using the following kinematics equation:

v = v_0 + at\\6.5 = 0 + 5a\\a = 1.3 m/s^2

Mass of the crate can be found by Newton’s Second Law:

F = Ma\\M = F/a = 144/1.3 = 110.7 kg

7 0
4 years ago
A copper rod of cross-sectional area 11.6 cm2 has one end immersed in boiling water and the other in an ice-water mixture, which
julia-pushkina [17]

Answer:

0.686 g of ice melts each second.

Solution:

As per the question:

Cross-sectional Area of the Copper Rod, A = 11.6\ cm^{2} = 11.6\times 10^{- 4}\ m^{2}

Length of the rod, L = 19.6 cm = 0.196 m

Thermal conductivity of Copper, K = 390\ W/m.^{\circ}C

Conduction of heat from the rod per second is given by:

q = \frac{KA\Delta T}{L}

where

\Delta T = 100^{\circ} - 0^{\circ} = 100^{\circ}C = temperature difference between the two ends of the rod.

Thus

q = \frac{390\times 11.6\times 10^{- 4}\times 100}{0.196} = 228.48\ J/s

Now,

To calculate the mass, M of the ice melted per sec:

M = \frac{q}{L_{w}}

where

L_{w} = Latent heat of fusion of water = 333 kJ/kg

M = \frac{228.48}{333\times 10^{3}} = 6.86\times 10^{- 4}\ kg = 0.686\ g

5 0
4 years ago
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