Question

A frog in a hemispherical pod finds that he just floats without sinking in a fluid of density 1.35 g/cm3. If the pod has a radius of 5.00 cm and negligible mass, what is the mass of the frog?

Answer 1

Answer:

Mass of the frog M = 706.85 Kg

Explanation:

Given Data:

The density of fluid is: ρo=1.30g/cm3

The radius of pod is: R=5cm

The expression for volume of pod is

Vo=4/3πR^3

The frog in a hemisphere pod just float without sinking so the buoyancy force applied on pod by fluid that is weight of fluid displaced.

The expression for buoyancy fore that is weigh of fluid displaced is

f=ρoVog

The expression for weight of floating object is

Wg=Mg

Here M  is mass of frog

The buoyancy force equal to weight of the floating object

f=Wg ρo Vo g=MgM=ρoVo

Substitute the value and solve the above expression

M=ρoVo=ρo4/3πR^3

$M= 1.35\times\frac{4}{3}\pi5^3$

M= 706.85834 Kg

Answer 2

Answer:

706.5 g

Explanation:

density of fluid, d = 1.35 g/c.c

According to the principle of flotation

Weight of the frog = Buoyant force acting on the frog

V x density of frog x g = V x density of fluid x g

So, the density of frog = density of pod

Mass of frog = volume of frog x density of frog

M = 4/3 πr³ x d

M = 4/3 x 3.14 x 5 x 5 x 5 x 1.35

M = 706.5 g

Thu,s the mass of frog is 706.5 g .