Answer: 4) Concentrate it
Explanation:
Answer:
Immiscible
Explanation:
Not sure what kind of substance but this is form liquids.
Answer:
a. 581.4 Pa
b. 3.33x10⁻⁴ mol/L
c. 3.49x10⁻⁴ mol/L
d. 0.015 g/L
Explanation:
a. By the Raoult's Law, the partial pressure of a component of a gas mixture is its composition multiplied by the total pressure, so:
pA = 0.9532*6.1
pA = 5.81452 mbar
pA = 5.814x10⁻³ bar
1 bar ----- 10000 Pa
5.814x10⁻³ bar--- pA
pA = 581.4 Pa
b. Considering the mixture as an ideal gas, let's assume the volume as 1,000 L, so by the ideal gas law, the total number of moles is:
PV = nRT
Where P is the pressure (610 Pa), V is the volume (1 m³), n is the number of moles, R is the gas constant (8.314 m³.Pa/mol.K), and T is the temperature.
n = PV/RT
n = (610*1)/(8.314*210)
n = 0.3494 mol
The number of moles of CO₂ is (V = 0.9532*1 = 0.9532 m³):
n = PV/RT
n = (581.4*0.9532)/(8.314*210)
n = 0.3174 mol
cA = n/V
cA = 0.3174/953.2
cA = 3.33x10⁻⁴ mol/L
c. c = ntotal/Vtotal
c = 0.3494/1000
c = 3.49x10⁻⁴ mol/L
d. The molar masses of the gases are:
CO₂: 44 g/mol
N₂: 28 g/mol
Ar: 40 g/mol
O₂: 32 g/mol
CO: 28 g/mol
The molar mass of the mixture is:
M = 0.9532*44 + 0.027*28 + 0.016*40 + 0.0008*28 = 43.36 g/mol
The mass concentration is the molar concentration multiplied by the molar mass:
3.49x10⁻⁴ mol/L * 43.36 g/mol
0.015 g/L
The molarity of the stock solution of luminol is 1.2 M
<u><em>calculation</em></u>
step 1: find the moles of luminol using (moles= mass/molar mass) formula
molar mass of Luminol= 177 g/mol
moles is therefore= 16.0 g/ 177 g/mol=0.0904 moles
Step 2: find the molarity using (molarity= moles/volume in liters) formula
convert Ml into liters = 75.0/1000= 0.075 L
molarity is therefore= 0.0904 moles/ 0.075 L= 1.2M
Answer:
The answer to your question is: 6 moles of HNO₃
Explanation:
Data
Volume = 25 ml
Concentration = 6 M HNO₃
Diluted 100 ml
Formula
Molarity = # moles / volume
# of moles = Volume x Molarity
Process
# of moles = 0.10 x 6
= 6 moles