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gizmo_the_mogwai [7]
3 years ago
6

Choose two of the following scientists: Anton Lavoisier, John Dalton, JJ Thomson, Robert Millikan, Ernest Rutherford, James Chad

wick, & Niels Bohr. Describe their experiments and discoveries. Tell how that changed the atomic theory.
Chemistry
1 answer:
elixir [45]3 years ago
6 0

Answer:

John Dalton:

John Dalton was the scientist who introduced atomic theory in the field of chemistry. Dalton worked on different gases and formulated this theory. The main points of Dalton's theory are:

  • Every element present is made up of atoms.
  • Atoms of an elements are have the same same properties whereas these properties are different for each element.
  • According to his theory, an atom could not be broken down.
  • Different atoms combine or get separated from each other during a chemical reaction.

Ernest Rutherford:

Ernest Rutherford is known as the father of nuclear physics due to his impressing research work on radioactivity of atoms. Rutherford was the first scientist to discover the nucleus of an atom and prove that the nucleus was charged. He also described that the electrons circle around the nucleus of an atom.

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Which statement about covalent bonds and electrons is true?
Illusion [34]
<span>D) Eectrons in covalent bonds are not always shared equally.</span>
3 0
3 years ago
Read 2 more answers
Complete the following molecular models to represent balanced equations by
trasher [3.6K]

Answer:

I do not know the Answer I'm just trying to get my point

Explanation:

Thank you

7 0
2 years ago
A gas sample occupies 350.0 mL at 546 mm Hg. What volume does the gas occupy at 652 mm Hg?​
leva [86]

Answer:

293.1 mL.

Explanation:

  • Boyle's law states that: at a constant temperature the pressure of a given mass of an ideal gas is inversely proportional to its volume.
  • It can be expressed as: <em>P₁V₁ = P₂V₂,</em>

P₁ = 546.0 mm Hg, V₁ = 350.0 mL.

P₂ = 652.0 mm Hg, V₂ = ??? mL.

<em>∴ V₂ = (P₁V₁)/(P₂)</em> = (546.0 mm Hg)(350.0 mL) / (652.0 mm Hg) = <em>293.1 mL.</em>

8 0
3 years ago
For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that w
Sindrei [870]

Answer:

75 mg

Explanation:

We can write the extraction formula as

x = m/[1 + (1/K)(Vaq/Vo)], where

x = mass extracted

m = total mass of solute

K = distribution coefficient

Vo = volume of organic layer

Vaq = volume of aqueous layer

Data:

m = 75 mg

K = 1.8

Vo = 0.90 mL

Vaq = 1.00 mL

Calculations:

For each extraction,

1 + (1/K)(Vaq/Vo) = 1  + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62  

x = m/1.62 = 0.618m

So, 61.8 % of the solute is extracted in each step.

In other words, 38.2 % of the solute remains.

Let r = the amount remaining after n extractions. Then  

r = m(0.382)^n.

If n = 7,

r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg

m = 75 - 0.088 = 75 mg

After seven extractions, 75 mg (99.999 %) of the solute will be extracted.

5 0
3 years ago
A. Reaction with what gas in the atmosphere makes natural rain water slightly acidic? (2 points)
Vlada [557]

Answer:

See explanation

Explanation:

On the pH scale acidity ranges from pH values of 0-6.9. Natural rain water is slightly acidic due to the presence of carbon dioxide in the atmosphere which is an anhydride of carbonic acid.

CO2(g) + H2O(l) -------> H2CO3(aq)

B. The equations that turn sulfur to sulfuric acid are;

S(l) + O2(g) -----> SO2(g)

2SO2(l) + O2(g) -----> 2SO3(g)

SO3(g) + H2SO4(l) -----> H2S2O7(l)

H2S2O7(l) + H2O(l) ----> 2H2SO4(l)

-

At pH 6, H^+ concentration = 1 * 10^-6 M

At pH 2, H^+ concentration = 1 * 10^-2 M

Hence;

1 * 10^-2/1 * 10^-6

= 10^4 times more acidic

5 0
3 years ago
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