First, you should convert the temperature unit to absolute temperature.
Second, you shoul graph the points. Then you will find a pretty linear correlations among the points.
You can pick between using the best fit line or you could observe that as you get to higher temperatures the linear behavior is "more perfect".
I found this best fit line:
P = 2.608T + 14
Then, for T = 423K
P = 2.608(423) + 14 = 1117 mmHg
If you prefer to use the last two points, this is the calculus:
[P - P1] / [T - T1] = [P2 - P1] / [T2 - T1]
[P - 960]/[423 -373] = [960 - 880] / [373- 343]
=> P = 1093.3 mmHg.
You can pick any of the results 1177 mmHg or 1093 mmHg, You need more insight to choose one of them: conditions and error of the experiment for example.
Answer:
element
Explanation:
it is use full for you thanks
The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L
From the question given above, the following data were obtained:
Initial pressure (P₁) = 8.5 atm
Initial volume (V₁) = 24 L
Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
Final pressure (P₂) = 13.5 atm
Final temperature (T₂) = 15 °C = 15 + 273 = 288 K
<h3>Final volume (V₂) =? </h3>
- The final volume of the gas can be obtained by using the combined gas equation as illustrated below:
Cross multiply
298 × 13.5 × V₂ = 204 × 288
4023 × V₂ = 58752
Divide both side by 4023
<h3>V₂ = 15 L </h3>
Therefore, the final volume of the gas is 15 L
Learn more: brainly.com/question/25547148
Answer:
30 cm³
Explanation:
Step 1: Given data
- Density of aluminum (ρ): 2.7 g/cm³
- Mass of aluminum (m): 81 g
- Volume occupied by aluminum (V): ?
Step 2: Calculate the volume occupied by aluminum
The density of aluminum is equal to its mass divided by its volume.
ρ = m/V
V = m/ρ
V = 81 g / 2.7 g/cm³
V = 30 cm³
