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kvasek [131]
3 years ago
11

The position equation for a particle is s of t equals the square root of the quantity 2 times t plus 1 where s is measured in fe

et and t is measured in seconds. find the acceleration of the particle at 4 seconds. 3 ft/sec2 one third ft/sec2 negative 1 over 27 ft/sec2 none of these
Physics
1 answer:
loris [4]3 years ago
8 0

Given that,

s = √(2t + 1)

Time, t = 4 s

Acceleration , a = ??

Since,

Acceleration = velocity / time

Velocity = distance/ time

Acceleration = distance/ time²

s/t² = √(2t+1)/t²

putting t = 4 sec, we have

a = √(2*4+1)/4²

a = √(5)/16

a= 0.139 ft/s²

Therefore, acceleration of the given particle will be 0.139 feet/ second².

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Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the sea, a rock sticks out a horizontal dis
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v_x = 4.87 m/s

Explanation:

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h = \frac{1}{2}gt^2

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3 0
3 years ago
If a jet travels 350 m/s, how far will it travel each second?
77julia77 [94]

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6 0
3 years ago
Read 2 more answers
(a) How many kilograms of water must evaporate from a 60.0-kg woman to lower their body temperature by 0.750ºC?
Mrrafil [7]

Answer:

69.69 g

Explanation:

Evaporation of water will take out latent heat of vaporization.  Let the mass of water be m and latent heat of vaporization of water be 2260000 J per kg

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