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3 years ago

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A non-conducting sphere of radius R = 3.0 cm carries a charge Q = 2.0 mC distributed uniformly throughout its volume. At what di

stance, measured from the center of the sphere, does the electric field reach a value equal to half its maximum value?

1 answer:

BlackZzzverrR [31]3 years ago

4 0

Answer:

$r =3 *\sqrt{2} = 4.24 cm$

Explanation:

given data

Radius of sphere 3.0 cm

charge Q = 2.0 m C

We know that maximum electric field is given as

$E_{MAX}= \frac{KQ}{r^{2}}$

electric field inside the sphere can be determine by using below relation

$\frac{KQ}{r^{2}}= \frac{1}{2}*\frac{KQ}{R^{2}}$

$r = \sqrt{2}R$

$r =3 *\sqrt{2} = 4.24 cm$

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Answer:

$2.1\times 10^{-12} c$

Explanation:

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Answer:

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We divide the first equation by the second equation to get:

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