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sladkih [1.3K]
4 years ago
14

State the objects in the universe that reflect light from stars

Physics
1 answer:
stepan [7]4 years ago
7 0
Everything in the universe that is not a star reflects light from Stars. Otherwise you can't see it.
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In this lab, you will use a cart and a track to explore Newton’s second law of motion. You will vary two different variables and
lutik1710 [3]

Questions that can be answered by doing the experiment and making observations scientifically:

1).  How long will it take to perform the complete experiment ?

2). Will it be daytime or night-time when the experiment begins ?

3). What will be the range of outdoor temperatures during the experiment ?

4). How many times will progress of the experiment be suspended in order to take phone calls ?

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4 years ago
6. What is the charge of an object that lost 1.20x1024 electrons?
Montano1993 [528]

Answer:

Hydrogen ions contains +1 charge while sulphate ions have 2 charge. ... No .of ions in one formula unit of MgC12 =3 Total no of ions in MgC12 =1.20x1024 x3=3.6x1024 ions.

Explanation:

8 0
3 years ago
PLEASE help can you give me the answers to the Light Unit Review Practice quiz I'm totally lost
solniwko [45]
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8 0
3 years ago
Name on contact force and one field force acting on you right now
kati45 [8]

Answer:

Contact forces are forces that require the actual contact (touching) of two pieces of matter. There are a variety of contact forces. A very common one is friction. Anytime that two surfaces are in contact with one another, there is friction between the two surfaces. A field force is a force that works at a distance. No touching is required. Gravity is a good example of a field force, because it works whether or not an object is touching something or touching nothing at all.

8 0
3 years ago
9. A ball is thrown straight up with an initial speed of 30 m/s. How long will it take to reach the top of its trajectory, and h
ziro4ka [17]

Answer:

1.) Time t = 3.1 seconds

2.) Height h = 46 metres

Explanation:

given that the initial velocity U = 30 m/s

At the top of the trajectory, the final velocity V = 0

Using first equation of motion

V = U - gt

g is negative 9.81m/^2 as the object is going against the gravity.

Substitute all the parameters into the formula

0 = 30 - 9.81t

9.81t = 30

Make t the subject of formula

t = 30/9.81

t = 3.058 seconds

t = 3.1 seconds approximately

Therefore, it will take 3.1 seconds to reach to reach the top of its trajectory.

2.) The height it will go can be calculated by using second equation of motion

h = ut - 1/2gt^2

Substitutes U, g and t into the formula

h = 30(3.1) - 1/2 × 9.8 × 3.1^2

h = 93 - 47.089

h = 45.911 m

It will go 46 metres approximately high.

6 0
3 years ago
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