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Tems11 [23]
3 years ago
12

After the right string is cut, the meterstick swings down to where it is vertical for an instant before it swings back up in the

other direction. What is the angular speed when the meterstick is vertical?.
Physics
1 answer:
abruzzese [7]3 years ago
4 0

The Angular Speed of the Meterstick after it becomes vertical is given as:

= 5.800 rad/s. This is computed using the formula for conservation of energy.

<h3>What is Angular Speed?</h3>

Angular Speed is defined as the measure of how quick or fast the central angle of a body that is rotational is changing in relation to time. Please see the attached for the full question.

<h3>What is the solution for the Angular Speed of the phenomena described?</h3>

Recall that the formula for conservation of energy is given as:

(1/2)(<em>Iω²) = mg(L/4) where

L=  Lenght and</em>

<em>m = Mass. Please refer to the attached questions.</em>

<em />

Factoring the moment of inertia about the pivot, we solve for the angular speed using the following formula:<em>

ω = </em>\sqrt{(mgL)/2I}

= \sqrt{(6g)/7L}

Hence, the angular speed is:

ω = 8.800rad/s

Learn more about Angular speed at:
brainly.com/question/540174

<em />

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A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
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Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

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The time taken by the object to hit the ground is calculated by:

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The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

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a,

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\displaystyle t=\sqrt{\frac{2*20}{9.8}}

\displaystyle t=\sqrt{4.0816}

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b.

The range is calculated now:

\displaystyle d=10\cdot 2.02

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

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