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Tems11 [23]
2 years ago
12

After the right string is cut, the meterstick swings down to where it is vertical for an instant before it swings back up in the

other direction. What is the angular speed when the meterstick is vertical?.
Physics
1 answer:
abruzzese [7]2 years ago
4 0

The Angular Speed of the Meterstick after it becomes vertical is given as:

= 5.800 rad/s. This is computed using the formula for conservation of energy.

<h3>What is Angular Speed?</h3>

Angular Speed is defined as the measure of how quick or fast the central angle of a body that is rotational is changing in relation to time. Please see the attached for the full question.

<h3>What is the solution for the Angular Speed of the phenomena described?</h3>

Recall that the formula for conservation of energy is given as:

(1/2)(<em>Iω²) = mg(L/4) where

L=  Lenght and</em>

<em>m = Mass. Please refer to the attached questions.</em>

<em />

Factoring the moment of inertia about the pivot, we solve for the angular speed using the following formula:<em>

ω = </em>\sqrt{(mgL)/2I}

= \sqrt{(6g)/7L}

Hence, the angular speed is:

ω = 8.800rad/s

Learn more about Angular speed at:
brainly.com/question/540174

<em />

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Answer:

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7 0
3 years ago
What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
Calculate the angular velocity of the neptune (orbital period of 165 earth period) in its orbit around the sun.
ludmilkaskok [199]
The correct answer is: Angular velocity =  1.208 * 10^{-9} rad/s

Explanation:
The angular velocity is given as:
ω = \frac{2\pi}{T} --- (1)

Where T = 165 * (365 days) * (24 hours/day) * (60 minutes/hour) * (60 seconds/minute) = 5203440000 s

Plug in the value in (1):
ω = \frac{2\pi}{5203440000} = 1.208 * 10^{-9} rad/s
7 0
3 years ago
Peak to peak value of voltage is
hram777 [196]

Answer: Peak-to-peak voltage is the distance from the lowest negative amplitude, or trough, to the highest positive amplitude, or crest, of the AC voltage waveform. In other words, peak-to-peak voltage is equal to the full height of the waveform. Peak-to-peak voltage can be found using peak voltage or RMS voltage.

Explanation:hope tht gave u a clue have a wonderful Christmas Eve time with your family!❄️

3 0
2 years ago
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Answer:

I'm taking a wild guess at c

Explanation:

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6 0
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