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Tems11 [23]
2 years ago
12

After the right string is cut, the meterstick swings down to where it is vertical for an instant before it swings back up in the

other direction. What is the angular speed when the meterstick is vertical?.
Physics
1 answer:
abruzzese [7]2 years ago
4 0

The Angular Speed of the Meterstick after it becomes vertical is given as:

= 5.800 rad/s. This is computed using the formula for conservation of energy.

<h3>What is Angular Speed?</h3>

Angular Speed is defined as the measure of how quick or fast the central angle of a body that is rotational is changing in relation to time. Please see the attached for the full question.

<h3>What is the solution for the Angular Speed of the phenomena described?</h3>

Recall that the formula for conservation of energy is given as:

(1/2)(<em>Iω²) = mg(L/4) where

L=  Lenght and</em>

<em>m = Mass. Please refer to the attached questions.</em>

<em />

Factoring the moment of inertia about the pivot, we solve for the angular speed using the following formula:<em>

ω = </em>\sqrt{(mgL)/2I}

= \sqrt{(6g)/7L}

Hence, the angular speed is:

ω = 8.800rad/s

Learn more about Angular speed at:
brainly.com/question/540174

<em />

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Nonamiya [84]

\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}

  • P is power
  • R is resistance

\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}

Hence

\\ \bull\tt\longrightarrow R\propto V

\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}

  • Therefore if power is low then resistance will be high.

The first bulb has less power hence it has greater filament resistance.

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2 years ago
A spherical helium filled balloon (B) with a hanging passenger cage being held by a single vertical cable (C) attached to Earth
Gre4nikov [31]

Answer:

The tension is  T  = 4326.7 \  N

Explanation:

From the question we are told that

   The  total mass is  m  =  200 \  kg

    The  radius is r = 5 \  m

     The  density of air is  \rho_a  =  1.225 \ kg/m^3

Generally the upward  force acting on the balloon is mathematically represented as

        F_N  =   T  + mg

=>     (\rho_a  *  V  *  g ) =   T  + mg

=>   T  =  (\rho_a  * V  *  g   )  - mg

Here V is the volume  of the spherical helium filled balloon which is mathematically represented as

      V  =  \frac{4}{3}  * \pi r^3

=>   V  =  \frac{4}{3}  * 3.142 *(5)^3

=>   V  = 523.67\  m^3

So

    T  = (1.225 *  523.67*  9.8 ) -  200 *  9.8

   T  = 4326.7 \  N

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