A 1.0-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength 0.20
1 answer:
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Answer:
The two skaters will move with a common speed of 1.19 m/s.
Explanation:
Given that,
Mass of Alex,
Initial velocity of Alex,
Mass of Barbara,
Initial velocity of Barbara,
After the collision, the two skaters move together at a common velocity. Let V is the common velocity. Using the conservation of momentum as :
Magnitude of final velocity:
So, the two skaters will move with a common speed of 1.19 m/s.
The answer is B
I used these equations then i putted it together.
Charge = number of ( electron or proton ) x charge of ( electron or proton )
Force = k x (q1 q2)/r²
I used these equations then i putted it together.
Charge = number of ( electron or proton ) x charge of ( electron or proton )
Force = k x (q1 q2)/r²
Answer:
towards right
towards left
Explanation:
= Mass of skater = 56 kg
= Mass of ball = 5 kg
v = Final velocity of ball = 7 m/s
u = Initial velocity of ball = 0
s = Distance the ball moved in the hand of the skater = 1 m
Moving left is considered and moving right is considered positive.
From kinematic equations of motion we have
So, the ball will move towards right with a magnitude of acceleration .
The force on the ball will be
The force on the ball is
The reaction force on the skater will be equal to the force on the ball but will have opposite direction.
So, the skater will move towards left with a magnitude of acceleration