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Veseljchak [2.6K]
3 years ago
10

The speed of a light wave in a certain transparent material is 0.701 times its speed in vacuum, which is 3.00×108 m/s . When yel

low light with a frequency of 5.23×1014 Hz passes through this material, what is its wavelength ???? in nanometers?
Physics
1 answer:
Temka [501]3 years ago
7 0

Answer:

402 nm

Explanation:

First, we find the speed of light in this medium:

v = 0.701 * c

v = 0.701 * 3 * 10^8

v = 2.103 * 10^8 m/s

Speed of a wave is given as the product of wavelength and frequency:

v = λf

Where λ = wavelength

Wavelength, λ, becomes:

λ = v/f

The frequency of the light is 5.23 * 10^14 Hz, therefore, wavelength will be:

λ = (2.103 * 10^8) / (5.23 * 10^14)

λ = 4.02 * 10^(-7) m = 402 nm

The wavelength of the light is 402 nm.

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Answer:

The frictional torque is \tau  = 0.2505 \ N \cdot m

Explanation:

From the question we are told that

   The mass attached to one end the string is m_1 =  0.341 \ kg

   The mass attached to the other end of the string is  m_2 =  0.625 \ kg

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At equilibrium the tension on the string due to the first mass is mathematically represented as

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substituting values

      T_1 =  0.341 * 9.8

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At equilibrium the tension on the string due to the  mass is mathematically represented as

      T_2 =  m_2 *  g

     T_2 = 0.625 * 9.8

      T_2 = 6.125 \ N

The  frictional torque that must be exerted is mathematically represented as

      \tau  =  (T_2 * r ) - (T_1 * r )

substituting values  

     \tau  =  ( 6.125 * 0.09 ) - (3.342  * 0.09 )

     \tau  = 0.2505 \ N \cdot m

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Explanation:

Given that

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From the diagram

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