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Veseljchak [2.6K]
3 years ago
10

The speed of a light wave in a certain transparent material is 0.701 times its speed in vacuum, which is 3.00×108 m/s . When yel

low light with a frequency of 5.23×1014 Hz passes through this material, what is its wavelength ???? in nanometers?
Physics
1 answer:
Temka [501]3 years ago
7 0

Answer:

402 nm

Explanation:

First, we find the speed of light in this medium:

v = 0.701 * c

v = 0.701 * 3 * 10^8

v = 2.103 * 10^8 m/s

Speed of a wave is given as the product of wavelength and frequency:

v = λf

Where λ = wavelength

Wavelength, λ, becomes:

λ = v/f

The frequency of the light is 5.23 * 10^14 Hz, therefore, wavelength will be:

λ = (2.103 * 10^8) / (5.23 * 10^14)

λ = 4.02 * 10^(-7) m = 402 nm

The wavelength of the light is 402 nm.

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A student is running to catch the campus shuttle bus, which is stopped at the bus stop. The student is runnign at a constant spe
Serggg [28]

Answer:

Part a)

t = 16.8 s

d = 100.8 m

Part b)

v_f = 2.86 m/s

Explanation:

Part a)

Constant speed by which the student will run is given as

v = 5 m/s

now after some time if student is going to overtake the position of bus

so here the final positions will be same

so we have

x_{bus} = x_{student}

0 + \frac{1}{2}at^2 + d = v_{student} t

\frac{1}{2}(0.170)t^2 + 60 = 5 t

0.085 t^2 - 5t + 60 = 0

so it is

t = 16.8 s

So student will run the total distance

d = vt

d = (6)(16.8)

d = 100.8 m

Part b)

Speed of bus when student reach the bus is given as

v_f = v_i + at

v_f = 0 + (0.170)(16.8)

v_f = 2.86 m/s

4 0
3 years ago
Explain three ways visual aids help you study
Katen [24]
Visual aids are tools that help to make an issue or lesson clearer or easier to understand and know (pictures, models, charts, maps, videos, slides, real objects etc.). ... Visual aids are those devices which are used in classrooms to encourage students learning process and make it easier and interesting.
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2 years ago
Explain why elements in the same family have similar physical and chemical properties
zhenek [66]
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3 years ago
A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ba
Lyrx [107]

Answer:

THE RUBBER BALL

Explanation:

From the question we are told that

      The mass of the rubber ball is m_r   =  2 \ kg

      The  initial  speed of the rubber ball is  u =  3 \ m/s

      The final speed at which it bounces bank v  - 3 \ m/s

      The mass of the clay ball  is  m_c =  2  \ kg

       The  initial  speed of the clay  ball is u = 3 \ m/s

       The final speed of the clay ball is  v = 0 \  m/s

Generally Impulse is mathematically represented as

       I  =  \Delta p

where \Delta  p is the change in the linear momentum so  

       I  =  m(v-u)

For the rubber  is  

        I_r  =  2(-3 -3)

       I_r  = -12\ kg \cdot  m/s

=>     |I_r|  = 12\ kg \cdot  m/s

For the clay ball

       I_c  =  2(0-3)

        I_c =  -6 \ kg\cdot \ m/s

=>    | I_c| =  6 \ kg\cdot \ m/s

So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball

       

8 0
3 years ago
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Tom llega primero a la superficie de el lago
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