Answer:
0.2v
Explanation:
Data given,
Diameter=18.5cm
Hence we can calculate the radius as D/2=18.5/2=9.25cm
radius=9.25cm/100=0.0925m
The area is calculated as
magnetic field, B=1.3T
time,t=0.18s
The flux is expressed as
since the loop is parallel, the angle is 0
Hence we can calculate the flux as
to determine the emf induced in the loop, we use Faraday law
Note the voltage is not negative but the negative sign shows the current flows in other to oppose the flux
Given: Altitude of satellite r = 13,300 Km convert to meter
r = 1.33 x 10⁷ m
Universal Gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²
Mass of the earth Me = 5.98 x 10²⁴ Kg
Required: Period of satellite T = ?
Formula: F = ma; Centripetal acceleration ac = V²/r F = GMeMsat/r²
Velocity of satellite V = 2πr/T
equate T from all given equation.
F = ma
GMeMsat/r² = MsatV²/r cancel Msat and insert V = 2πr/T
GMe/r² = (2πr)²/rT² Equate T or period of satellite
T² = 4π²r³/GMe
T² = 39.48(1.33 X 10⁷ m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)
T² = 9.29 x 10²² m³/3.99 x 10¹⁴ m³/s²
T² = 232,832,080.2 s²
T = 15,258.84 seconds or (it can be said around 4.24 Hr)
Answer: that’s chemistry not physics
Explanation:
Answer:
a) F₁ = F₂, F₃ = F₄, b) the correct answer is 3
Explanation:
a) In this exercise we have several action and reaction forces, which are characterized by having the same magnitude, but different direction and being applied to different bodies
Forces 1 and 2 are action and reaction forces F₁ = F₂
Forces 3 and 4 are action and reaction forces F₃ = F₄
as it indicates that the
b) how the car increases if speed implies that force 1> force3
F₁ > F₃
therefore the correct answer is 3
Answer:
The range of the projectile is 66.7 meters.
Explanation:
The range of a projectile is given by the following expression as :
..............(1)
The range can be calculated using equation (1). Putting the values of all parameters we get :
R = 66.7 meters
So, the range of the projectile is 66.7 meters. Hence, this is the required solution.
