Answer:
Radius of curvature of the mirror = 250 cm
Explanation:
Given:
Object distance from mirror = 250 cm (u=-250)
Object distance appears in mirror = 250 cm (v=-250)
Find:
Radius of curvature of the mirror
Computation:
Using mirror formula
1/f = 1/v + 1/u
1/f = 1/(-250) + 1/(-250)
f = (-250/2)
f = -125 cm or 125 cm
Radius of curvature of the mirror = 2(f)
Radius of curvature of the mirror = 2(125)
Radius of curvature of the mirror = 250 cm
No, it is the other way around. When an electron moves from one energy level to another energy level more distant from the nucleus, it gains, not emits energy. The closer it gets to the nucleus, the more energy it emits. If it is far from the nucleus, it gains more energy.