You are trying to find the amount of heat transferred between two substances. In order to do this, you plan

Help!!!!!!!!!!!!!!!!!plz!!!!!!!!!!!!!!!!!!!!!

Zarrin [17]

Wrap wire around B the nails

4 0

3 years ago

A dock worker applies a constant horizontal force of 80.5 N to a block of ice on a smooth horizontal floor. The frictional force

Eddi Din [679]

Answer:

(a). The mass of the block of ice is 62.8 kg.

(b). The distance is 24.192 m.

Explanation:

Given that,

Horizontal force = 80.5 N

Distance = 13.0 m

Time = 4.50 s

(a). We need to calculate the acceleration of the block of ice

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$13=0+\dfrac{1}{2}\times a\times(4.50)^2$

$a=\dfrac{13\times2}{(4.50)^2}$

$a=1.28\ m/s^2$

We need to calculate the mass of the block of ice

Using formula of force

$F = ma$

$m=\dfrac{F}{a}$

Put the value into the formula

$m=\dfrac{80.5}{1.28}$

$m=62.8\ kg$

(b). If the worker stops pushing at the end of 4.50 s,

We need to calculate the velocity

Using equation of motion

$v =u+at$

Put the value into the formula

$v=0+1.28\times4.50$

$v=5.76\ m/s$

We need to calculate the distance

Using formula of distance

$v = \dfrac{d}{t}$

$d=v\times t$

Put the value into the formula

$d=5.76\times4.20$

$d=24.192\ m$

Hence, (a). The mass of the block of ice is 62.8 kg.

(b). The distance is 24.192 m.

5 0

3 years ago

A. Calculate the electric potential energy stored in a capacitor that stores <img src="https://tex.z-dn.net/?f=3.40%20x%2010%5E%

sertanlavr [38]

Part a)

As we know that energy stored inside the capacitor is given as

$U = \frac{1}{2}CV^2$

for a given capacitor we know

$Q = CV$

Now we can use it in above equation to find the energy

$U = \frac{1}{2}QV$

$U = \frac{1}{2}(3.4\times 10^{-6})(24)$

$U = 40.8\times 10^{-6} J$

PART b)

If two negative charges are hold near to each other and then released

Then due to mutual repulsion they start moving away from each other

Due to mutual repulsion as the two charges moving away the electrostatic potential energy of two charges will convert into kinetic energy of the two charges.

So here as they move apart kinetic energy will increase while potential energy will decrease

Part c)

As we know that capacitance is given as

$C = \frac{Q}{V}$

here we know that

$Q = 3\times 10^{-10}C$

$V = 35 volts$

$C = \frac{3\times 10^{-10}}{35}$

$C = 8.6 \times 10^{-12} F$

5 0

3 years ago

Read 2 more answers

A vector has a magnitude of 30m at an angle of 225 degrees with respect to the positive x-axis and has a magnitude of 13m.what a

Aneli [31]

Answer:

I'm pretty sure this is not a complete question. My guess is that you are trying to add/subtract vectors. Vectors have both magnitude and direction, so vector A is pretty clear, but a magnitude of 13 (i'm guessing a resultant) without a direction is weird.

IF 13 is the magnitude of the resultant, vector B added to vector A could have any magnitude 17 ≤ B ≤ 43

It could have any direction of

θ = (225 - 180) ± arcsin(13/30)

θ = 45 ± 25.679...

70.679 ≤ θ ≤ 19.321

components of vector B would be

Bx = |B|cosθ

By = |B|sinθ

3 0

2 years ago

T=2pi square root 1/g solve for g.<br> Explanation would be really helpful.

Natalija [7]

I added individual steps for clarity. Note that g must be positive if the solution is to be real.

$T=2\pi \sqrt{\frac{1}{g}}=2\pi g^{-\frac{1}{2}}\\g^{-\frac{1}{2}} = \frac{T}{2\pi}\\(g^{-\frac{1}{2}})^{-2} = (\frac{T}{2\pi})^{-2}\\g = \frac{4\pi^2}{T^2}\,\,\,, g>0}$

Let me know if you have any questions.

7 0

2 years ago