Answer:
0.800 m/s²
Explanation:
First, calculate the angular acceleration:
ω = αt + ω₀
6.00 rad/s = α (3.00 s) + 0 rad/s
α = 2.00 rad/s²
Now calculate the angular velocity at t = 2.00 s:
ω = αt + ω₀
ω = (2.00 rad/s²) (2.00 s) + 0 rad/s
ω = 4.00 rad/s
Calculate the linear velocity:
v = ωr
v = (4.00 rad/s) (0.0500 m)
v = 0.200 m/s
Finally, calculate the centripetal acceleration:
a = v² / r
a = (0.200 m/s)² / (0.0500 m)
a = 0.800 m/s²
Complementary angles are those whose sum is 90 degrees, right?, then let's find A, A=72 degrees, because its mid point is 36 deg. Then, B = 18 degrees and its mid point is 9 degrees! :)
Answer:
The maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°
Explanation:
Given;
coefficient of static friction, μ = 0.4
for the block to remain stationary on the inclined plane, force pushing the block upward must be equal to the force acting downwards.
μR = mgsinθ
μmgcosθ = mgsinθ
μcosθ = sinθ
μ = sinθ/cosθ
μ = tanθ
θ = tan⁻¹(0.4) = 21.8°
Therefore, the maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°
