Answer:
s = 30330.7 m = 30.33 km
Explanation:
First we need to calculate the speed of sound at the given temperature. For this purpose we use the following formula:
v = v₀√[T/273 k]
where,
v = speed of sound at given temperature = ?
v₀ = speed of sound at 0°C = 331 m/s
T = Given Temperature = 10°C + 273 = 283 k
Therefore,
v = (331 m/s)√[283 k/273 k]
v = 337 m/s
Now, we use the following formula to calculate the distance traveled by sound:
s = vt
where,
s = distance traveled = ?
t = time taken = 90 s
Therefore,
s = (337 m/s)(90 s)
<u>s = 30330.7 m = 30.33 km</u>
The elastic potential energy stored in the car's spring during the process is 3.75 J
<h3>Determination of the spring constant</h3>
From the question given above, the following data were obtained:
K = F/e
K = 15 / 0.5
K = 30 N/m
<h3>Determination of the potential energy</h3>
- Spring constant (K) = 30 N/m
PE = ½Ke²
PE = ½ × 30 × 0.5²
PE = 15 × 0.25
PE = 3.75 J
Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J
Learn more about energy stored in spring:
brainly.com/question/4280346
The collision of car 2 is more violent (because more impulse is exerted)
Explanation:
The collision which is more violent is the one in which more impulse is exchanged.
The impulse exerted by each car on the wall is equal to the change in momentum of the car:
where
m is the mass of the car
is the change in velocity
For the car 1,
m = 1000 kg
(the sign is negative because the velocity of the car has changed from 100 km/h to 0 km/h)
So the magnitude of the impulse of car 1 is
For the car 2,
m = 1200 kg
So the magnitude of the impulse of car 2 is
So, car 2 exerts a larger impulse, therefore its impact is more violent.
Learn more about impulse and change in momentum:
brainly.com/question/9484203
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