Which of the following statements about iron filings placed upon glass resting on top of a bar magnet is false?

Please help and explain please thank youu

vekshin1

Answer:

2)

Series circuits = D & E

parallel circuits = C & F

3)

Circuit C is connected in parallel and circuit D is connected in series.

Circuit D and E are the same, despite the switch is located in a different position, they are working in series.

Circuits C and F are the same, they are connected in parallel.

There will be only one bulb in on mode and it is in the circuit F.

Explanation:

In the attached image, we can see a serial circuit and a parallel circuit. Serial circuits are characterized by sharing the same current, if the current step is interrupted (opening the switch), the current will not flow and no element (light bulbs off) will work. When a circuit is connected in parallel, they share the same voltage within the circuit. All resistive elements or bulbs are located between nodes 1 and 2, so they share the same voltage.

The special case are the circuits C and F, both are connected in parallel. But in circuit C the switch is near to the voltage source, therefore when the switch is unplugged there won't be the main current and the bulbs will be off.

In-circuit F, when the switch is off only the bulb near to the switch won't work the other bulb will be working because the main current is passing through it.

3 0

3 years ago

A circuit consists of a lightbulb, capacitor, battery, and open switch all in series. After the switch is closed, describe what

Savatey [412]

Answer:

Explanation:

Since this is an RC circuit, an RC circuit can be used to provide various time delays. The capacitor is connected in parallel across the lightbulb. WITH the battery connected , when the switch is closed , the capacitor voltage increases towards the battery voltage at a rate determined by the lightbulb resistance and the capacitance of the capacitor (called the time constant (τ)). The bulb will not emit any light and will act like an open circuit until the voltage across the capacitor reaches a certain level that can bright the bulb, when this voltage is reached the lightbulb brights gradually and the capacitor discharges through it, the lightbulb turns off again because the capacitor voltage drops fast and the capacitor recharges again and the lightbulb brights again

7 0

4 years ago

Plants appear green because they do not absorb the green wavelengths of light. What happens to those green light waves when they

arlik [135]

Explanation:

it is reflected all the other colors such as red is absorbed

8 0

3 years ago

Read 2 more answers

The current theory of the structure of the

IRISSAK [1]

1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

1)

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

2)

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

$1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s$

So, the speed is:

$v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s$

So, we can now find the kinetic energy:

$K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J$

3)

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

$K=\frac{1}{2}mv^2$

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0

3 years ago

An isolated capacitor with capacitance C = 1 µF has a charge Q = 45 µC on its plates.a) What is the energy stored in the capacit

Roman55 [17]

Answer:

a) Energy stored in the capacitor, $E = 1.0125 *10^{-3} J$

b) Q = 45 µC

c) C' = 1.5 μF

d) $E = 6.75 *10^{-4} J$

Explanation:

Capacitance, C = 1 µF

Charge on the plates, Q = 45 µC

a) Energy stored in the capacitor is given by the formula:

$E = \frac{Q^2}{2C} \\\\E = \frac{(45 * 10^{-6})^2}{2* 1* 10^{-6}}\\\\E = \frac{2025 * 10^{-6}}{2}\\\\E = 1012.5 *10^{-6}\\\\E = 1.0125 *10^{-3} J$

b) The charge on the plates of the capacitor will not change

It will still remains, Q = 45 µC

c) Electric field is non zero over (1-1/3) = 2/3 of d

From the relation V = Ed,

The voltage has changed by a factor of 2/3

Since the capacitance is given as C = Q/V

The new capacitance with the conductor in place, C' = (3/2) C

C' = (3/2) * 1μF

C' = 1.5 μF

d) Energy stored in the capacitor with the conductor in place

$E = \frac{Q^2}{2C} \\\\E = \frac{(45 * 10^{-6})^2}{2* 1.5* 10^{-6}}\\\\E = \frac{2025 * 10^{-6}}{3}\\\\E = 675 *10^{-6}\\\\E = 6.75 *10^{-4} J$

4 0

3 years ago