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3 years ago

Which of the following statements about iron filings placed upon glass resting on top of a bar magnet is false?

Physics

1 answer:

marin [14]3 years ago

7 0

Statements A, B, and C are true.

Statement D is false.

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In the example of jumping off a chair, what is the impulse that will stop your fall?

liq [111]

Answer:

You will reach both your arms out to break your fall and save your head.

Explanation:

It common sense you don't want your head injured. Do you?

5 0

3 years ago

Micah knows that a car had a change in velocity of 15 m/s. What does micah need to determine acceleration.

katrin2010 [14]

The time component is needed. The acceleration is the change of velocity divided by the time in when this change of velocity happens.

4 0

3 years ago

Read 2 more answers

A man applies a force of 100 N to a rock for 60 seconds, but the rock does not move what is the amount of work done by the man o

Art [367]

600. I forgot the measurement. but 600 is correct

6 0

3 years ago

You stand on a bridge above a river and drop a rock into the water below from a height of 25 m. (Assume no air resistance)

Ilia_Sergeevich [38]

PART a)

here when stone is dropped there is only gravitational force on it

so its acceleration is only due to gravity

so we will have

$a = g = 9.8 m/s^2$

Part b)

Now from kinematics equation we will have

$y = v_i t + \frac{1}{2} at^2$

now we have

y = 25 m

so from above equation

$25 = 0 + \frac{1}{2}(9.8 )t^2$

$t = 2.26 s$

Part c)

If we throw the rock horizontally by speed 20 m/s

then in this case there is no change in the vertical velocity

so it will take same time to reach the water surface as it took initially

So t = 2.26 s

Part D)

Initial speed = 20 m/s

angle of projection = 65 degree

now we have

$v_x = vcos\theta$

$v_x = 20 cos65 = 8.45 m/s$

$v_y = vsin\theta$

$v_y = 20 sin65 = 18.13 m/s$

PART E)

when stone will reach to maximum height then we know that its final speed in y direction becomes zero

so here we can use kinematics in Y direction

$v_f - v_y = at$

$0 - 18.13 = (-9.8) t$

$t = 1.85 s$

so it will take 1.85 s to reach the top

5 0

3 years ago

Question 26 suppose that a constant force is applied to an object. newton's second law of motion states that the acceleration of

ololo11 [35]

The answer is 6 kg the mass of the second object. By using Inversely proportional formula it means that (14 kg) (3 m/s²) = M (7 m/s²). Where M is the mass of the second object. For the Newton’s second law of motion formula which is: Force = mass x acceleration, we have:

F = (14 kg) (3 m/s²) = 42 N

Therefore:

42 N = M (7 m/s²)

M = (42 N) / (7 m/s²)

M = 6 kg mass of the second object

4 0

3 years ago