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Darya [45]
3 years ago
12

It is easier to lift the same load by using three pulley system than by using two-pulley system. why give reason.​

Physics
1 answer:
tresset_1 [31]3 years ago
7 0
<h2>QUESTION:- It is easier to lift the same load by using three pulley system than by using two-pulley system.</h2>

<h2>ANSWER:- IN CASE OF IDEAL PULLEY SYSTEM</h2>

<h2>REASON:- </h2>

Logic behind is lies behind the mechanical advantage of the provided bt the Pulley system.

as if we calculate the mechanical advantage of the 2 Pulley system we will have the value 2

And if we will calculate the mechanical advantage of the 3 pulley system then we will get the value of 3

so due to extra mechanical advantage we feel it easy to move with 3 pulley system then 2 Pulley system

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

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Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its
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Generally angular velocity is mathematically represented as

            w = \frac{2 \pi}{T}

Where T is the period which is given as 1.6 days = 1.6 *24 *60*60 = 138240 sec

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         w = \frac{2 \pi}{138240}

             = 4.54*10^ {-5} rad /sec

At the point when the rocket is on a circular orbit  

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              \frac{GMm}{r^2} = mr w^2

Where  G is the universal gravitational constant with a value  G = 6.67*10^{-11}

            M is the mass of the earth with a constant value of M = 5.98*10^{24}kg

            r is the distance between earth and circular orbit where the rocke is found

               Making r the subject

                     r = \sqrt[3]{\frac{GM}{w^2} }

                        = \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }

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The orbital speed is represented mathematically as

                   v=wr

Substituting value

                  v= (5.78*10^7)(4.54*10^{-5})

                     v= 2.6*10^{3} m/s    

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                            v_e = \sqrt{\frac{2GM}{r} }

Substituting values

                             = \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }

                             v_e= 3.72 *10^3 m/s

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