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galben [10]
4 years ago
11

Why is it necessary that all three thermometers were at approximately the same distance from the light bulb

Physics
1 answer:
iris [78.8K]4 years ago
8 0
I'm assuming it was to keep the data consistent? The further you are from a heat source the less heat will get to you as the temperature tries to reach equilibrium and the waves start to spread out, so you should keep everything the same distance to get consistent results. I don't have any information so this is just my assumption
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Susan
maxonik [38]
D. Was a leader in the woman's suffrage movement
7 0
3 years ago
Light from an argon laser strikes a diffraction grating that has 4,917 lines per cm. The first-order principal maxima are separa
miss Akunina [59]

Answer:

Wavelength is 4.8x10^-7m

Explanation:

See attached file

3 0
3 years ago
Determine Force. 589J of work was accomplished over a distance of 1100m, how much force was exerted? Include the correct units.
LiRa [457]

Answer:

Explanation:

Given:

A = 589 J

D = 1 100 m

____________

F - ?

A = F·D

F = A / D = 589 / 1100 ≈ 0.54 N

5 0
1 year ago
A loop of current-carrying wire has a magnetic dipole moment of 5. 0 10–4 am2. if the dipole moment makes an angle of 57° with a
Digiron [165]

The potential energy will be 1.46*10^-4J.

To find the answer, we have to know about the torque acting on a current loop in a uniform magnetic field.

<h3>How to find the potential energy of the loop?</h3>
  • We have the expression for torque acting on a current loop in a uniform magnetic field as,

                         \tau=MBsin\theta

where; M is the magnetic dipole moment, B is the magnetic field , and theta is the angle between M and B.

  • As we know that, the torque is equal to force times the perpendicular distance. Thus, it is equivalent to the work done. This work is stored as the potential energy in the loop.
  • Thus, the potential energy will be,

            \tau=W=U=MBsin\theta=5*10^{-4}*0.35*sin57=1.46*10^{-4}J

Thus, we can conclude that, the potential energy will be 1.46*10^-4J.

Learn more about the torque here:

brainly.com/question/27949876

#SPJ4

7 0
2 years ago
The maximum speed with which you can throw a stone is about 25 m/s. Can you hit a window 50 m away and 13 m up from the point wh
Nookie1986 [14]

Answer:

no, the maximum height = 12.3m

Explanation:

The equation for the trajectory of the ball for a given angle can be derived from:

(1) x=cos\phi v_0t

and

(2) y=-\frac{1}{2}gt^2 +sin\phi v_0t

Combining equation 1 and 2:

(3) y=xtan\phi -\frac{gx^2}{2cos^2\phi v_0^2}

Taking the derivative:

(4) \frac{dy}{d\phi}=\frac{xsec^2\phi}{v_0^2}(v_0^2-gxtan\phi)

Setting equation 4 equal to zero to calculate the maximum angle:

(5) \phi=tan^{-1}(\frac{v_0^2}{gx})

Plugging equation 5 back into equation2 confirms, the trajectory can't reach the target. The maximum height is 12.3m.

3 0
3 years ago
Read 2 more answers
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