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poizon [28]
3 years ago
15

Takumi works in his yard for 45 minutes each Saturday. He works in the morning, and he wears sunscreen and a hat each time he wo

rks in the yard.
What does Takumi hope to reduce through his actions?
Physics
2 answers:
MrMuchimi3 years ago
9 0

takumi wants to reduce the chance of getting a sunburn


Arte-miy333 [17]3 years ago
6 0

takumi wants to reduce the chance of getting a sunburn :D

<em>hope this helps!</em>

<em>have a great day :)</em>

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What types of alternative fuels did bp pursue after browne became ceo in 1995?
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Answer:solar energy

Explanation:

This is the energy gotten from sunlight to knock off electrons from fee atom.

This panel contains photovoltaic cells

8 0
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What is the current when a typical static charge of 0.234~\mu\text{c}0.234 μc moves from your finger to a metal doorknob in 0.59
Black_prince [1.1K]
The current is defined as the quantity of charge Q that passes through a certain location in a time \Delta t:
I= \frac{Q}{\Delta t}
Using the data of the problem, we find:
I= \frac{Q}{\Delta t} = \frac{0.234 \mu C}{0.595 \mu s}=\frac{0.234\cdot 10^{-6} C}{0.595 \cdot 10^{-6} s}=0.39 A
4 0
3 years ago
Consider the previous situation. Under what condition would the acceleration of the center of mass be zero? Keep in mind that F1
Nana76 [90]

Answer:

a) m₁ = m₂  F₁ₓ = F₂ₓ

b) m₁ << m₂   F₂ₓ =0

Explanation:

This interesting exercise is unclear your statement, so that in a center of mass system has an acceleration of zero it is necessary that the sum of the forces on each axis is zero, to see this we write Newton's second law

     ∑ F = m a

for acceleration to be zero implies that the net force is zero.

we must write the expression for the center of mass

        x_{cm} = 1 / M (m₁ x₁ + m₂ x₂)

now let's use the derivatives

      a_{cm} = d² x_{cm}/dt² = 1 / M (m₁ a₁ + m₂a₂)

where M is the total mass M = m₁ + m₂

     so that the acceleration of the center of mass is zero

               0 = 1 / M (m₁ a₁ + m₂a₂)

               m₁ a₁ = - m₂ a₂

In the case that we have components on the x axis, the modulus of the two forces are equal and their direction is opposite, therefore

   F₁ₓ = -F₂ₓ

b)r when the two masses are equal , in the case of a mass greater than the other m₁ << m₂

      acm = d2 xcm / dt2 = 1 / M (m1 a1 + m2a2)

so that the acceleration of the center of mass is zero

               0 = 1 / M (m1 a1 + m2a2)

               m1 a1 = - m 2 a2

with the initial condition, we can despise m₁, therefore

                0 = m₂a₂

 if we use Newton's second law

              F₂ = 0

       

I tell you that in this case with a very high mass difference the force on the largest mass must be almost zero

4 0
3 years ago
Do you remove the positive or negative first on a car battery?
nevsk [136]

Answer:

negative at first.

Explanation:

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4 0
1 year ago
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Gnesinka [82]

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4 0
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