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4 years ago

What is the French word for shepherds crook

Physics

2 answers:

alukav5142 [94]4 years ago

8 0

"shepherd's crook" means "houlette de berger" in french

wolverine [178]4 years ago

6 0

The answer would be:

Houlette de berger.

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At its closest approach, a moon comes within 200,000 km of the planet it orbits. At that point, the moon is 300,000 km from the

krok68 [10]

Answer:

s₁ = 240,000 km

Explanation:

The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,

s = s₁ + s₂

where,

s = total distance between the focuses = ?

s₁ = distance between f1 and moon = 200,000 km

s₂ = distance between f₂ and moon = 300,000 km

Therefore,

s = 200,000 km + 300,000 km

s = 500,000 km

Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:

s = s₁ + s₂

500,000 km = s₁ + 260,000 km

s₁ = 500,000 km - 260,000 km

s₁ = 240,000 km

5 0

3 years ago

Consider the power dissipated by the two circuits in the video. The ratio of power dissipation in the parallel circuit to that i

rjkz [21]

Answer:

D. 1/9

Explanation:

Firstly, draw the circuits, then you solve for resistance in series with the formula- R1 + R2... And in parallel- 1/R1 + 1/R2...

Then after getting your resistance, use the formula for power that relates with resistance and voltage.

This the ratio will be 1/9. The parallel circuit has 1/9 the resistance of the series circuit. Since the potential difference across the two circuits is the same, this implies that the parallel circuit will give out 9 times more power than the series circuit.

3 0

3 years ago

Read 2 more answers

A force of 6n is exerted on a cart that is carrying a rock and produces an acceleration of 2 m/s2. if the cart has a mass of 1 k

Alex777 [14]

F=ma
m=f/a
m=6N/2 m per secon per second
m=3 kg.
If the cart is 1 kg then 3kg-1kg is 2kg.
The mass of the rock is 2kg.

4 0

4 years ago

Ear "popping" is an unpleasant phenomenon sometimes experienced when a change in pressure occurs, for example,in an airplane. If

marshall27 [118]

Answer:

H = 0.00058m = 0.58mm of Mercury

h = 160m for popping at 8000m

Explanation:

Air density decreases with altitude (increasing height).

At sea level air density = 1.22kg/m^3

while at 3000m above it is approximately 0.8 kg/m^3

ASSUMPTION:

we neglect the change in density across 100m vertically

density of mercury = 13600kg/m ^3

we equate the pressure for mercury and air

AIR(pgh) = Mercury(pgh)

0.8 * g * 100 = 13600 * g * H

H = 0.00058m = 0.58mm of Mercury

At even farther heights, the air density further drops

at 8000m above it is 0.52kg/ m^3 (source:https://www.engineeringtoolbox.com/standard-atmosphere-d_604.html)

***for the ear to pop again, it has to experience same change in pressure as of at 3000m

Change in P for AIR at 3000m = Change in P for AIR at 8000m

ASSUMPTION : gravitational acceleration does not change with altitude

pgh = pgh

0.8 * g * 100 = .5 * g *h

h = 160m

3 0

4 years ago

Which of following does not constitute a breach of academic integrity?

Ivan

Answer:

No options

Explanation:

3 0

3 years ago