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Andreyy89
3 years ago
15

A UHF television loop antenna has a diameter of 11 cm. The magnetic field of a TV signal is normal to the plane of the loop and,

at one instant of time, its magnitude is changing at the rate 0.16 T/s. The magnetic field is uniform. What emf is induced in the antenna
Physics
2 answers:
Doss [256]3 years ago
7 0

Answer:

-0.00152 V

Explanation:

Parameters given:

Diameter of the loop = 11 cm = 0.11m

Rate of change of magnetic field, dB/dt = 0.16 T/s

Radius of the loop = 0.055m

The area of the loop will be:

A = pi * r²

A = 3.142 * 0.055²

A = 0.0095 m²

The EMF induced in a loop of wire due to the presence of a changing magnetic field, dB, in a time interval, dt, is given as:

EMF = - N * A * dB/dt

In this case, there's only one loop, so N = 1.

Therefore:

EMF = -1 * 0.0095 * 0.16

EMF = -0.00152 V

The negative sign indicates that the current flowing through the loop acts opposite to the change in the magnetic field.

Inessa05 [86]3 years ago
7 0

Answer:

The induced emf is 0.00152 V

Explanation:

Given data:

d = 11 cm = 0.11 m

r=\frac{d}{2} =\frac{0.11}{2} =0.055m

The area is:

A=\pi r^{2} =\pi *(0.055^{2} )=0.0095m^{2}

The induced emf is:

E=-A\frac{dB}{dt} =-(0.0095)*(0.16)=-0.00152V

The negative indicates the direction of E.

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Applying the given values we get

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Part b)

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Additional Information:

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Explanation:

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2. The torque of the arm, T_{arm}  

Assuming the arm is just being stretched and there is no rotation going on,

                        T_{Deltoid} = 0

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F_{d} is the force of the deltiod

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The force of the deltoid muscle is,

                                 F_{d} = \frac {r_{a}F_{a}sin\alpha_{a}}{r_{d}sin\alpha_{d}}

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