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4 years ago

Please help no need to explain

Mathematics

1 answer:

Grace [21]4 years ago

5 0

Answer:

the b-20=9

Step-by-step explanation:

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The sum of two consecutive odd integers is -120. find the two integers

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The numbers are 59 and 61

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3 years ago

Find the missing term (x^12)^5 x (x^-2)^9 x what =(x^40)^5

Annette [7]

Answer:

$x^{158}$

Step-by-step explanation:

We are given,

$(x^{12} )^{5} \times (x^{-2} )^{9} \times y = (x^{40} )^{5}$ .

It is required to find the value of y.

Now, on simplifying above equation, we get,

$x^{60} \times x^{-18} \times y = x^{200}$

i.e. $x^{42} \times y = x^{200}$

i.e. $y = x^{200} \times x^{-42}$

i.e. $y = x^{158}$

Hence, the missing term is $x^{158}$ .

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3 years ago

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At the end of the day, Mr. Díaz drains the pool. The equation

Charra [1.4K]

Answer: 6 minutes.

Step-by-step explanation: You can use a graphing calculator to see the exact graph, but you're trying to figure out what value of x gives you a y of 0. -50 times 6 is 300, plus 300 equals 0.

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3 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

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3 years ago

Add and Subtract Decimals to

Bogdan [553]

It should be 0.4 cause 0.4 is the same as 0.40

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3 years ago

Please help no need to explain ​

Please help no need to explain