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Bond [772]
3 years ago
6

The distance between the image and the object in a plane mirror is 40cm if the distance of the object is reduced by 9.2cm, what

is the mirror?​
Chemistry
1 answer:
finlep [7]3 years ago
4 0

Answer:

<u></u>

  • <u>10.8 cm</u>

Explanation:

The question is:

<h2>What is the distance of the object from the mirror?</h2>

To answer this question, you must learn that, for plane mirrors, the distance of the object from the mirror is equal to the distance of the image formed behind the mirror.

For instance if you stand 1 meter away from a mirror (a plane one) the position of the image of you will be 1 meter behind the mirror.

Here, the initial distance between the image and the object is 40 cm. Then, the distance between the image and the miror is 20 cm, such as it is the distance between the object and the mirror.

That the distance of the object is reduced by 9.2 cm, must be understood as that the object was placed 9.2 cm closer to the mirror.

Then, the new distance of the object from the mirror is 20 cm - 9.2 cm = 10.8 cm. ← answer

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HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

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K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression :

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CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression :

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

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Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

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HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression of HC_2H_3O_2 will be:

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

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The equilibrium expression of Co(H_2O)_6^{3+} will be:

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

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CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression of CH_3NH_3^+ will be:

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

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