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Dovator [93]
3 years ago
8

What can you conclude about the classification of krypton?

Chemistry
1 answer:
cluponka [151]3 years ago
3 0

Answer:

Krypton is considered to be non-toxic.

Characteristics: Krypton is a colorless, odorless, inert gas. Although it is extremely unreactive krypton can react with the very reactive gas fluorine.

Classification: Krypton is a noble gas

State: gas

Atomic weight: 83.80

Electron shells: 2,8,18,8

<u>Toxic to Superman</u>

Hope this helps :)

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Determine the number of centiliters in 2.4 x 10^3 milliliters.
AnnZ [28]
2.4(10^3)

=2.4*10^3

=2.4*(10*10*10)

=2400 <span>milliliters

To </span>centiliters is<span> 2400mL= <u>240.0000cl. </u> </span>



8 0
3 years ago
Use the periodic table to calculate the percent composition of hydrogen in hexane.
valina [46]

Answer:

A)16.3% (Hexane's formula is C6H14)

3 0
3 years ago
This number tells you the number of each type of atom in a compound.
KonstantinChe [14]

Answer:

avogadro's constant

Explanation:

this is the fixed number of the atoms in the molecule of an element

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7 0
3 years ago
Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH
Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

    No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{12 g}{60 g/mol}

                           = 0.2 mol

Molarity of acetic acid is calculated as follows.

              Density = \frac{mass}{volume}

                 1 g/ml = \frac{100 g}{volume}

                    volume = 100 ml

Hence, molarity = \frac{\text{no. of moles}}{volume}

                           = \frac{0.2 mol}{0.1 L}

                           = 2 mol/l

As reaction equation for the given reaction is as follows.

     NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O

So,          moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

          x \times 1 M = 10 mL \times 2 M     (as 1 L = 1000 ml)

                        x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.                    

6 0
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