A chemist has one solution that is 80% acid and another solution that is 30% acid. how much of the second (30%) solution is need
1 answer:
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The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
<h3>What is the half-life of a radioactive material?</h3>The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.
The half-life, , the age, t, and amount remaining,
, of a radioactive material are related by the formula below:
Half-life of carbon-14 = 6000 years
For the Egyptian papyrus with 63% of its original carbon-14 atoms:
For the Aboriginal charcoal with 22% of its original carbon-14 atoms:
For the Mayan headdress with 79% of its original carbon-14 atoms:
Neanderthal skull with 3% of its original carbon-14 atoms:
Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
Learn more about half-life at: brainly.com/question/26689704
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Answer:
(3R,4R)-4-bromohexan-3-ol
Explanation:
In this case, we have reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.
Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)
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