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Simora [160]
3 years ago
8

Write the balanced neutralization reaction that occurs between H 2 SO 4 and KOH in aqueous solution. Phases are optional. neutra

lization reaction: Suppose 0.650 L of 0.490 M H 2 SO 4 is mixed with 0.600 L of 0.280 M KOH . What concentration of sulfuric acid remains after neutralization? concentration:
Chemistry
1 answer:
icang [17]3 years ago
3 0

Answer:

0.19 M is the concentration of H₂SO₄ that remains after neutralization

Explanation:

In a neutralization reaction we produce water and a salt, formed by the cation and anion from the correspond base and correspond acid.

Acid: H₂SO₄

Base: KOH

We determine the reaction: H₂SO₄  +  2KOH →  K₂SO₄  +  2H₂O

1 mol of sulfuric reacts with 2 moles of hydroxide to produce 1 mol of sulfate and 2 moles of water.

We determine the moles of each reactant ( M . volume)

0.650L . 0.490mol/L = 0.32 moles of acid

0.600L . 0.280mol/L = 0.17 moles of base

In this question: "What concentration of sulfuric acid remains after neutralization" it is shown that the excess reactant is the H₂SO₄

We verify that, 2 moles of base can react with 1 mol of acid

So, 0.17 moles of base must react with (0.17 .1) / 2 = 0.085 moles

Moles of acid that remains, after the reaction is complete: 0.32 - 0.085 =

0.235 moles.

To determine the concentration, our total volume is (base vol + acid vol)

0.650L + 0.600L = 1.250L → M (mol/L) = 0.235 mol / 1.250L = 0.19 M

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3 years ago
Calculate the pH of the following simple solutions:
IceJOKER [234]

Answer :

(1) pH = 1.27

(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

<u>(1) 53.1 mM HCl</u>

Concentration of HCl = 53.1mM=53.1\times 10^{-3}M

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= 53.1\times 10^{-3}M

pH : It is defined as the negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH=-\log (53.1\times 10^{-3})

pH=1.27

<u>(2) 0.223 M KOH</u>

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (0.223)

pOH=0.65

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35

<u>(3) 53.1 mM HCl + 0.223 M KOH</u>

Buffer : It is defined as a solution that maintain the pH of the solution by adding the small amount of acid or a base.

It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

5 0
3 years ago
A mixture of gases at a total pressure of 95 kPa contains N₂, CO₂, and O₂. The partial pressure of the CO₂ is 24 kPa and the par
Zinaida [17]

Answer:

23 kPa = Partial pressure O₂

Explanation:

In a mixture of gases, the sum of partial pressure of each gas that contains the mixture = Total pressure

Total pressure = Partial pressure N₂ + Partial pressure CO₂ + Partial pressure O₂

95 kPa = 48 kPa + 24 kPa + Partial pressure O₂

95 kPa - 48 kPa - 24 kPa = Partial pressure O₂

23 kPa = Partial pressure O₂

7 0
3 years ago
Which action would shift this reaction away from solid calcium fluoride and toward the dissolved ions? which action would shift
ANTONII [103]
Hello!

The chemical reaction for the dissolving of calcium fluoride is the following:

CaF₂(s) ⇄ Ca⁺²(aq) + 2F⁻(aq)

In this reaction, and according to Le Chatelier's principle, the action that would shift this reaction away from solid calcium fluoride and towards the dissolved ions is the removing of fluoride ions.

Le Chatelier's principle
states that in an equilibrium reaction, the system would shift in the opposite direction of the changes. If we remove fluoride ions from the system, it will shift towards the formation of more fluoride ions by dissolving more Calcium Fluoride to achieve equilibrium again.

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3 years ago
Describe the process you used to build a model. What did you do first? second?
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First read the introduction.

Seconds look at the pictures how to build it.
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