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3 years ago

C6H12O6 + 6O2 ---> 6H2O + 6CO2

Chemistry

1 answer:

Ivahew [28]3 years ago

3 0

Answer:

24e⁻ are transferred by the reaction of respiration.

Explanation:

C₆H₁₂O₆ + 6O₂ → 6 H₂O + 6CO₂

This is the reaction for the respiration process.

In this redox, oxygen acts with 0 in the oxidation state on the reactant side, and -2 in the product side - REDUCTION

Carbon acts with 0 in the glucose (cause it is neutral), on the reactant side and it has +4, on the product side - OXIDATION

6C → 6C⁴⁺ + 24e⁻

In reactant side we have a neutral carbon, so as in the product side we have a carbon with +4, it had to lose 4e⁻ to get oxidized, but we have 6 carbons, so finally carbon has lost 24 e⁻

6O⁻² + 6O₂ + 24e⁻ → 6O₂²⁻ + 6O⁻²

In reactant side, we have 6 oxygen from the glucose (oxidation state of -2) and the diatomic molecule, with no charge (ground state), so in the product side, we have the oxygen from the dioxide with -2 and the oxygen from the water, also with -2 at the oxidation state. Finally the global charge for the product side is -36, and in reactant side is -12, so it has to win 24 e⁻ (those that were released by the C) to be reduced.

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4 years ago

What is the approximate time of death if the body temperature was 15.6°C?

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Answer:

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3 years ago

Identify structure(s) for all constitutional isomers with the molecular formula C4H8 that have one double bond. Select all that

Alchen [17]

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u> $C_4_H8$ in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>

<u />

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>

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Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>

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See figure 1 to further explanations.

I hope it helps!

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3 years ago

Using the formula M=dx v, Calculate the mass of a liquid with a density of

valkas [14]

Answer:

<h3>The answer is 122.5 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

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density = 17.5 g/mL

We have

mass = 17.5 × 7

We have the final answer as

Hope this helps you

8 0

3 years ago