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3 years ago

C6H12O6 + 6O2 ---> 6H2O + 6CO2

Chemistry

1 answer:

Ivahew [28]3 years ago

3 0

Answer:

24e⁻ are transferred by the reaction of respiration.

Explanation:

C₆H₁₂O₆ + 6O₂ → 6 H₂O + 6CO₂

This is the reaction for the respiration process.

In this redox, oxygen acts with 0 in the oxidation state on the reactant side, and -2 in the product side - REDUCTION

Carbon acts with 0 in the glucose (cause it is neutral), on the reactant side and it has +4, on the product side - OXIDATION

6C → 6C⁴⁺ + 24e⁻

In reactant side we have a neutral carbon, so as in the product side we have a carbon with +4, it had to lose 4e⁻ to get oxidized, but we have 6 carbons, so finally carbon has lost 24 e⁻

6O⁻² + 6O₂ + 24e⁻ → 6O₂²⁻ + 6O⁻²

In reactant side, we have 6 oxygen from the glucose (oxidation state of -2) and the diatomic molecule, with no charge (ground state), so in the product side, we have the oxygen from the dioxide with -2 and the oxygen from the water, also with -2 at the oxidation state. Finally the global charge for the product side is -36, and in reactant side is -12, so it has to win 24 e⁻ (those that were released by the C) to be reduced.

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The fluoride rinse in dental offices usually contains sodium fluoride. Sodium fluoride can be prepared from the reaction between

Bad White [126]

The chemical reaction in which number of atoms of each element present in the reactant side is equal to the number of atoms of that element in product side, such reactions are said to be a balanced chemical reaction.

The chemical symbol for sodium is $Na$ .

The chemical symbol for fluorine gas is $F_2$ .

The chemical symbol for sodium fluoride is $NaF$

The sodium fluoride is prepared from the reaction between sodium metal and fluorine gas can be written as:

$Na (s)+F_2(g) \rightarrow NaF(s)$

The above reaction is not balanced as the number of fluorine atoms are not same on reactant and product side. So, in order to balance the reaction we will multiply $Na$ with 2 on reactant side and $NaF$ with 2 on product side. Thus, the balanced reaction will be:

$2Na (s)+F_2 (g)\rightarrow 2NaF(s)$

Thus, the balanced chemical equation is $2Na (s)+F_2 (g)\rightarrow 2NaF(s)$ .

3 0

3 years ago

Read 2 more answers

A binary compound created by reaction of nitrogen and an unknown element E contains 30.46% N and 69.54% E by mass. If the formul

aleksklad [387]

Answer:

15.95

Explanation:

This question is a modification of the calculation of the empirical formula of a compound given its percent composition and atomic weights of the elements in the compound.

Here we are given the formula and the percent composition, so we know that there are 4 atoms of E per 2 atoms of N so lets solve using the information given.

In 100 grams of the binary compound we have

30.46 g N

69.54 g E

The number of moles is the mass divided by atomic weight:

mol N = 30.46 g / A.W N = 30.46 g / 14.00 g/mol = 2.18 mol N

mol E = 65.54 g / A.W E

Thus,

4 mol E/ 2 mol N = ( 69.54 g/ A.W E ) / 2.18

2 A.E = 65.54 g / 2.18 ⇒ A.W E = 69.54 g / ( 2 x 2.18 ) = 15.94 g

So the A.W is 15.94 g/mol which is close the atomic weight of O.

5 0

3 years ago

If 8.6 g of ch4 and 5.9 g of o2 react, what is the mass, in grams, of h2o that is produced?

Alenkasestr [34]

This may seem confusing because they give you two masses, but all you have to do is pick one to do the calculations. Personally, I would pick O2, since the molar mass is easier to calculate. The answer would be 3.3 g (rounded for sig figs). To get this, first take the 5.9 grams of O2 and convert it to moles by dividing by the molar mass of oxygen gas, which is 32. Then, multiply both by the mole-mole ratio, which is 2:2, or simply 1:1. After that, multiply that by 18g, which is the molar mass of water to get grams of water.

REMEMBER, you have to write and balance the chemical equation before you can do any of that work.
That happens to be CH4 + 2O2 => CO2 + 2H2O

7 0

3 years ago

Which two formulas represent compounds

SVEN [57.7K]

CO2 ; H20- They are the only ones that, on both sides, combined with another element and bonding of atoms

4 0

3 years ago

Isoelectric point. The isoelectric point (pI) is the pH at which a molecule has no net charge. The amino acid glycine has two io

timama [110]

Answer:

pI = 6.16

Explanation:

The pI is given by the average of the pKas that are involved. In this case,

Pka of carboxylic acid was given as 2.72 and that of the Amino group was given as 9.60. the average would then be ½(2.72+9.60)

= 6.16

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3 years ago