Answer:
The smell of a chocolate is from the presence of volatile compounds present in the chocolate bar which at room temperature readily changes phase from solid to liquid to vapor or gas
Explanation:
There are nearly 600 identified compounds present in a chocolate bar and out of these, there are volatile components which gives the chocolate bar its distinctive aroma.
These volatile chocolate contents readily change phase from solid to vapor, with very short duration liquid phase.
For example, 3 methylbutanal, vanillin, and several organic compounds which are known to be readily volatile.
Answer:
mol times or devided by molar volume
Answer:
2.05moles
Explanation:
The balanced chemical equation in this question is as follows;
Sn + 2H2SO4 → SnSO4 + SO2 + 2H2O
Based on the above equation, 2 moles of H2SO4 reacted to produce 1 mole of SnSO4
However, the mass of SnSO4 produced is 219.65 grams. Using mole = mass/molar mass, we can find the number of moles of SnSO4 produced.
Molar mass of SnSO4 where Sn = 118.7, S = 32, O = 16
= 118.7 + 32 + 16(4)
= 150.7 + 64
= 214.7g/mol
mole = 219.65/214.7
mole = 1.023mol
Therefore, if 2 moles of H2SO4 reacted to produce 1 mole of SnSO4
1.023 mol of SnSO4 produced will cause: 1.023 × 2/1
= 2.046moles of H2SO4 to react.
All mixtures contain only one kind of atom.
~Mschmindy
The balanced equation for the reaction between Mg and O₂ is as follows
2Mg + O₂ --> 2MgO
stoichiometry between Mg and O₂ is 2:1
number of Mg reacted - 4.00 mol
if 2 mol of Mg reacts with 1 mol of O₂
then 4.00 mol of Mg requires - 1/2 x 4.00 = 2.00 mol of O₂
then the mass of O₂ required - 2.00 mol x 32.0 g/mol = 64.0 g
64.0 g of O₂ is required for the reaction
