The launch speed of a horizontally launched projectile is 13.28 m/s.
<h3>
Time of motion of the projectile</h3>
The time of motion is calculated as follows;
t = √(2h / g)
where;
- h is height of the cliff
- g is acceleration due to gravity
t = √(2 x 19.3 / 9.8)
t = 1.98 s
<h3>Launch speed of the projectile</h3>
X = Vxt
Vx = X/t
Vx = (26.3)/(1.98)
Vx = 13.28 m/s
Thus, the launch speed of a horizontally launched projectile is 13.28 m/s.
Learn more about horizontal speed here: brainly.com/question/24949996
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Answer: Graph C is the correct option
Explanation:
The question is incomplete, please remember to submit the whole question :)
However, the rest of the question with its corresponding figures is below:
Assume that positive momentum is to the right, which of the following best represents the momentum of the cart of mass m as a function of time before and after the collision?
The initial momentum
of the cart with mass
(before the collision) is:
(1) Note the negative sign indicates the direction of cart's velocity (to the left, as seen in the first image attached)
On the other hand, the final momentum
of both carts (after the inelastic collision) is:
(2)
So, according to this, the correct graph tha best represents the situation is C. Since before the collision the momentum is negative, then both carts slow down after the collision (
), and taking into account the linear momentum is directly proportional to the velocity
(although is in the positive direction) is less than
.
The period of oscillation of the system is 12.56 s
Explanation:
The period of oscillation of a spring-mass system is given by

where
m is the mass attached to the spring
k is the spring constant
For the system in this problem, we have
m = 40 kg
k = 10 N/m
Substituting into the equation, we find

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Opposite force in the opposite.