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3 years ago

A charged particle is placed in a space. The particle experiences a force. What can be concluded?

Physics

2 answers:

alexandr1967 [171]3 years ago

5 0

Answer: A.

The space contains a magnetic field

Explanation:

A charged particle is surrounded by electric field and exerts force on other charges in the field, attracting or repelling them.

But a charged particles in a magnetic field can escape into infinity without ever stopping due to magnetic force. We can therefore conclude that the space contains a magnetic field

Lyrx [107]3 years ago

5 0

Answer:

Explanation:

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How can we drop eggs the fewest amount of times without breaking it?

enot [183]

Answer:

drop in water

Explanation:

follow me m mm m

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3 years ago

A comet is first seen at a distance of d astronomical units from the Sun and it is traveling with a speed of q times the Earth’s

saw5 [17]

To solve this problem it is necessary to take into account the concepts of Gravitational Force and Kinetic Energy.

The kinetic energy is given by the equation:

$F= \frac{mv^2}2$

La energía gravitacional por,

$F=\frac{GM_cm}{d}$

Where m is the mass, v is the velocity, G the gravitational constant $M_e$ the mass of the earth, m the mass of the sun and d the distance ..

The sum of the energies, we must be a total energy

$E= \frac{mv^2}2+\frac{GM_em}{d}$

By the type of orbit we know that

E> 0 is a hyperbolic orbit

E = 0 is a parabolic orbit

E <0 is a closed orbit.

In the case of hyperbolic orbit

E>0

$\frac{mq^2}{2}-\frac{GM_em}{d}>0\\\frac{qv^2_e}{2}>\frac{GM_em}{d}\\q^2d>2\frac{GM_e}{v^2_e}\\q^2d>2$

The case of the comet is a closed orbit, so,

E<0

$\frac{mv^2}2+\frac{GM_em}{d}$

For parabolic orbit

E=0

$\frac{mv^2_eq^2}{2}-\frac{GM_cm}{d}=0\\\frac{v^2_eq^2}{2}=\frac{GM_c}{d}\\q^2d=2\frac{GM_e}{v^2_e}\\q^2d=2$

For the sun and the earth

$\frac{m_ev_e^2}{r}=\frac{GM_em_e}{r^2}$

$v^2_e=\frac{GM_e}{r}\\\frac{GM_e}{v_e}=r$

where $R \approx 1AU$

$q^2d$ For elliptical orbit

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3 years ago

A block slides on a frictionless, horizontal surface with a speed of 1.32 m/s. The block encounters an unstretched spring and co

Rus_ich [418]

Answer:

Explanation:

The given time is 1 / 4 of the time period

So Time period of oscillation.

= 4 x .4 =1.6 s

When the block reaches back its original position when it came in contact with the spring for the first time , the block and the spring will have maximum

velocity. After that spring starts unstretching , reducing its speed , so block loses contact as its velocity is not reduced .

So required velocity is the maximum velocity of the block while remaining in contact with the spring.

v ( max ) = w A = 1.32 m /s.

3 0

3 years ago

Distance from any point on a wave to an identical point on the next wave?

lesantik [10]

It's called the "Wavelength". It corresponds to <span>the distance from any point on a wave to an identical point on the next wave and could also be from crest to crest or trough to trough.

Hope this helps !

Photon</span>

6 0

3 years ago

A 50 kg person receives an absorbed dose of gamma radiation of 20 millirads. What is the total energy absorbed?.

Masteriza [31]

For a 50 kg person receives an absorbed dose of gamma radiation of 20 millirads, the total energy absorbed is mathematically given as

E=0.1457J

<h3>What is the total energy absorbed?</h3>

Generally, the equation for the total energy absorbed is mathematically given as

E=mass*gamma radiation

Therefore

E=50*20*19^{-3}

E=0.1457J

In conclusion, the total energy absorbed

E=0.1457J