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nasty-shy [4]
3 years ago
11

A plane has a cruising speed of 250 miles per hour when there is no wind. at this speed, the plane flew 300 miles with the wind

in the same amount of time it flew 200 miles against the wind. find the speed of the wind.
Physics
1 answer:
snow_lady [41]3 years ago
7 0

V = speed of the plane with no wind = 250 mph

v  = speed of wind

consider the motion of the plane while traveling with the wind :

V' = speed of plane travelling in the direction of wind = V + v = 250 + v

d' = distance traveled = 300 miles

t' = time taken to travel the distance

time taken to travel the distance is given as

t' = d'/V'

t' = 300/(250 + v)                                           eq-1


consider the motion of the plane while traveling against the wind :

V'' = speed of plane travelling against the direction of wind = V - v = 250 - v

d'' = distance traveled = 200 miles

t'' = time taken to travel the distance

time taken to travel the distance is given as

t'' = d''/V''

t'' = 200/(250 - v)                                           eq-2

Given that :

time taken to travel 300 miles = time taken to travel 200 miles

t' = t''

using eq-1  and eq-2

300/(250 + v)  = 200/(250 - v)

3/(250 + v)  = 2/(250 - v)

750 - 3 v = 500 + 2 v

5 v = 250

v = 50 mph


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If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. Wh
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 v = -v₀ / 2

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when the initial velocity is vo it reaches just the negative plate so v = 0

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now they tell us that the initial velocity is half

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at the point where turn v = 0              

          0 = v₀² /4  - 2 a y '

          v₀² /4 = 2 (v₀² / 2y)  y’

          y = 4 y'

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We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.

         v² = v₀² -2a y’

         v² = 0 - 2 (v₀² / 2y) y / 4

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Two asteroids identical to those above collide at right angles and stick together; i.e, their initial velocities were perpendicu
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Answer:

velocity = 62.89 m/s  in 58 degree measured from the x-axis

Explanation:

Relevant information:

Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.

Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

Before collision Momentum of A = 1000 x 100 = $ 10^5$ kg - m/s in the right direction.

Before collision Momentum of B = 2000 x 80 = 1.6 x $ 10^5$  kg - m/s in upward direction.

Mass of System of after collision = 1000 + 2000 = 3000 kg

Now applying the Momentum Conservation, we get

Initial momentum in right direction = final momentum in right direction = $ 10^5$

And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x $ 10^5$

So, $ V_x = \frac{10^5}{3000} $  = $ \frac{100}{3} $  m/s

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Therefore, velocity is = $ \sqrt{V_x^2 + V_y^2} $

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And direction is

tan θ = $ \frac{V_y}{V_x}$     = 1.6

therefore, $ \theta = \tan^{-1}1.6 $

                   = $ 58 ^{\circ}$  from x-axis

4 0
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