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nasty-shy [4]
3 years ago
11

A plane has a cruising speed of 250 miles per hour when there is no wind. at this speed, the plane flew 300 miles with the wind

in the same amount of time it flew 200 miles against the wind. find the speed of the wind.
Physics
1 answer:
snow_lady [41]3 years ago
7 0

V = speed of the plane with no wind = 250 mph

v  = speed of wind

consider the motion of the plane while traveling with the wind :

V' = speed of plane travelling in the direction of wind = V + v = 250 + v

d' = distance traveled = 300 miles

t' = time taken to travel the distance

time taken to travel the distance is given as

t' = d'/V'

t' = 300/(250 + v)                                           eq-1


consider the motion of the plane while traveling against the wind :

V'' = speed of plane travelling against the direction of wind = V - v = 250 - v

d'' = distance traveled = 200 miles

t'' = time taken to travel the distance

time taken to travel the distance is given as

t'' = d''/V''

t'' = 200/(250 - v)                                           eq-2

Given that :

time taken to travel 300 miles = time taken to travel 200 miles

t' = t''

using eq-1  and eq-2

300/(250 + v)  = 200/(250 - v)

3/(250 + v)  = 2/(250 - v)

750 - 3 v = 500 + 2 v

5 v = 250

v = 50 mph


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Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27
densk [106]

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n\times\dfrac{m}{V_{c}\times N_{A}}

n=\dfrac{\rho\timesV_{c}\times N}{m}....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100

\rho=5.98

We calculate the mass of the alloy

m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100

m=111.15

Put the value into the equation (I)

n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

5 0
4 years ago
How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N
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Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

           acceleration of object (a) = 22.35 m/s^{2}

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                        mass of an object (m) = ?

From Newton's second law of motion;

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                          or, m= \frac{120}{22.35} kg

                           ∴ m = 5.36 kg

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