Answer:
(a) Heat transfer to the environment is: 1 MJ and (b) The efficiency of the engine is: 41.5%
Explanation:
Using the formula that relate heat and work from the thermodynamic theory as:
solving to Q_out we get:
this is the heat out of the cycle or engine, so it will be heat transfer to the environment. The thermal efficiency of a Carnot cycle gives us: 
where T_Low is the lowest cycle temperature and T_High the highest, we need to remember that a Carnot cycle depends only on the absolute temperatures, if you remember the convertion of K=°C+273.15 so T_Low=150+273.15=423.15 K and T_High=450+273.15=723.15K and replacing the values in the equation we get:
Answer:
5500000 millimeters
Explanation:
1 kilometre= 1000 meter
5.5 km=5.5 * 1000
=5500
Now,
1 metre = 1000 millimetres
5500 metre=1000*5500
=5500000 mm
Answer:
d = 3.8857 g/cm^3
Explain:
Formula/: d = m/V
Hope this helps!
(a brainliest would be appreciated)
Answer:
TRUE
Explanation:
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Explanation:
a) How much work is done by gravity?
- w = f x d
- w = 950 x 10 x 5.5 = 52250j
b) How much work is done by tension?
- v²=u²+2as
- 0.75²=0.25²+2a x5.5
- 0.56=0.06+2a x5.5
- 2a x5.5 = 0.56 - 0.06
- 2a x 5.5 =0.5
- 11a=0.5
- a = 0.5/11 = 0.05m/s²
w = f x d
w = 950 x 0.05 x 5.5 = 261.25j
