What is the momentum of a 12 kg ball travelling at 35 m/s?
2 answers:
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Answer:
Explanation:
consider the mass of each train car be m
m₁ = m₂ = m₃ = m
speed of the three identical train
u₁ = u₂ = u₃ = 1.8 m/s
m₄ = m u₄ = 4.5 m/s
m₅ = m u₅ = 0 (initial velocity )
final velocity
v₁ = v₂ = v₃ = v₄ = v₅ = v
using conservation of momentum
m₁u₁ + m₂u₂ + m₃u₃ + m₄u₄ + m₅u₅ = m₁v₁ + m₂v₂ + m₃v₃ + m₄v₄ + m₅v₅
m (1.8 + 1.8 + 1.8 +4.5) = 5 m v
1 m = 1 000 000 ym
converted other way we can say that:
1 ym =
m
Now, since we have ym^2 which is ym*ym which means:
1 ym^2 =
m
we have 1,5 ym^2 which means that answer is:
converted other way we can say that:
1 ym =
Now, since we have ym^2 which is ym*ym which means:
1 ym^2 =
we have 1,5 ym^2 which means that answer is: