A 20.-N force stretches the spring by 1.00 m - 0.50 m = 0.50 m, so by Hooke's law the spring constant is k such that
20. N = k (0.50 m)
⇒ k = (20. N) / (0.50 m) = 40 N/m
Answer:
4276.98 years
Explanation:
t = age of the sample in numbers of years
T = half life of the carbon-14 isotope = 5730 yrs
λ = decay constant of carbon-14
decay constant is given as



A₀ = activity of Carbon-14 in living plants
A = activity of Carbon-14 after time "t" = (0.596) A₀
Using the equation



t = 4276.98 years
False, while holding the book it means there is no work done on the book.