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Gemiola [76]
3 years ago
10

Which pair of molecules is not a polar bond? OA. N-O OO B. C-O C.O-H OD. 0-0

Chemistry
1 answer:
hodyreva [135]3 years ago
4 0
Od. 0-0 does not pair of the Molecules bid it’s polar bond due to certain pairs of molecules not being present within its presentations
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You have 4.5 x 10^24 particles of C3H8. How many grams are present?
Citrus2011 [14]

Answer:

33 g.

Explanation:

Hello there!

In this case, for these particle-mole-mass relationships problems, it is necessary for us to recall the following equivalence statement, based off the molar mass of the involved compound, C3H8, one mole of particles and the Avogadro's number:

1mol=44.11g=6.022x10^{23}molecules

In such a way, we can set up the following expression for the calculation of the mass in the given particles of propane:

4.5x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules} *\frac{44.11g}{1mol}\\\\33g

Best regards!

3 0
2 years ago
The solubility of copper(i) chloride is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl (cucl=99.00 g mol-1).
garri49 [273]
Convert  Mg  to  grams
1g =1000mg  what  about  3.91  Mg
=  3.91mg  x  1g/1000mg=  3.91  x10^-3 g
moles= mass/molar mass
that  is  3.91  x10^-3g  /99 g/mol=3.95 x10^-5moles
concentration=   moles  /  vol   in  liters

that  is  3.95  x10^-5/100  x1000=  3.94  x10^-4M

equation for  dissociation  of  CUCl=   CUCl---->  CU^+   +Cl^-

Ksp=(CU+)(CI-)
that  is  (3.95  x10^-4)(3.95  x10^-4)
Ksp=  1.56  x10^-7
3 0
2 years ago
Read 2 more answers
How many moles are in 50 g of CO2
murzikaleks [220]

Answer:

1.1 mol

Explanation:

n=m/M, where n is moles, m is mass, and M is molar mass.

M of CO2 = 12.01+16.00+16.00 = 44.01g/mol

n=50g/44.01g/mol

n = 1.13610543 mol

n ≈ 1.1 mol

Hope that helps

8 0
2 years ago
Convert 5.4 of NaCl to grams
labwork [276]
The answer is 315.59095 grams :)
7 0
2 years ago
What liquid is got from copper ii and Ammonia gas?​
11111nata11111 [884]

Answer:

deep blue solution of tetramminecopper [Cu(NH3)4]2+ complex ion.

Explanation:

6 0
2 years ago
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