The balanced chemical reaction is written as:
<span>NaOH + HCl → NaCl + H2O
We are given the amount of sodium hydroxide to be used up in the reaction. This will be the starting point for the calculation.
2.75 x 10^-4 mol NaOH ( 1 mol H2O / 1 mol NaOH ) ( 18.02 g H2O / 1 mol H2O ) = 4.96 x 10^-3 g H2O</span>
I would love to help but it is 3 or is it 3 million?
Coefficient:
a. 2 9 8 10
b. 1 2 2 1
c. 1 1 2 1
Hope this helped:)
Part 1)
when the balanced equation for this reaction is:
and by using ICE table
Mg(OH)2(s) ↔ Mg2+(aq) + 2OH-(aq)
initial 0 0
change +X +2X
Equ X 2X
When KSp expression = [Mg2+][OH-]
when we have KSp = 5.61 x 10^-11
and when we assumed [Mg2+] = X
and [ OH-] = (2X)^2
when we assume X is the value of molar solubility of Mg(OH)2
so, by substitution:
5.61 x 10^-11 = 4X^3
∴ X = 2.4 x 10^-4 M
∴ molar solubility of Mg(OH)2 = X = 2.4 x 10^-4 M
Part 2)
the molar solubility of Mg(OH)2 in 0.16 m NaOH we assumed it = X
by using the ICE table:
Mg(OH)2(s) → Mg2+(aq) + 2OH-
initial 0 0.16m
change +X +2X
equ X (0.16+2x)
when Ksp = [mg2+][OH-]^2
5.61 x 10^-11 = X * (0.16+2X)^2 by solving for X
∴ X = 1.3 x 10^-5 M
∴ the molar solubility = X = 1.3 x 10^-5 M
<span>Topic & Statement (ask a question)
Conduct Research
Form a Hypothesis
Conduct an Experiment
Collect Data
Analyze Results
Form Conclusions
Report & Present</span>
