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ser-zykov [4K]
3 years ago
6

4. Three people are pushing a 500 kg of box in the same direction. Applied forces are 30 N, 20 N, and 10 N respectively. If the

acceleration of the box is 0.02 m/s2, what is the magnitude of a force created by friction?
Physics
1 answer:
Serjik [45]3 years ago
6 0

Answer:50N

Explanation:

mass=500kg

Total force=30+20+10=60N

Acceleration=0.02m/s^2

Resultant force=mass x acceleration

Resultant force=500 x 0.02

Resultant force=10N

Frictional force=total force - resultant force

Frictional force=60-10=50N

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Answer:

\nu =1166\times 10^{20}Hz  

Explanation:

We have given the rest mass of SPARTYON = 945 times of mass of electron

We know that mass of electron =9.11\times 10^{-31}kg

So mass of SPARTYON =945\times 9.11\times 10^{-31}=8608.95\times 10^{-31}kg

Speed of light c=3\times 10^8m/sec

According to Einstein equation energy is given by

E=mc^2=8608.95\times 10^{-31}\times (3\times 10^{8})^2=77480.55\times 10^{-15}j

Now according to planks's rule

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So 77480.55\times 10^{-15}=6.6\times 10^{-34}\nu

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it is seen that in a balloon filled with air,if we press one side of the balloon the other side bulges out.why is it so???​
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When we apply pressure on the one side of balloon the other side bulges out due to the movement of gas to other side.

<h3>What happen when we press one side of the balloon?</h3>

If we press one side of the balloon, the other side bulges out because the gas that present on one side moves to the other side where there is no pressure. The body of balloon is elastic so when we apply pressure the other side bulges out.

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