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alina1380 [7]
3 years ago
13

Why do concave lenses always form virtual images?

Physics
2 answers:
kolbaska11 [484]3 years ago
5 0

Answer:

Explanation:

There are two types of images formed by the lenses or mirrors.

1. Real image: When two refracted or reflected rays actually meet at a point after refraction or reflection, the image formed is real.

2. Virtual image: When two refracted or reflected rays appear to meet at a point after refraction or reflection, the image formed is virtual.

A concave lens is a diverging lens, it means when the rays of light incident on the concave lens, then after refraction, the rays diverges from its original path. Thus, they cannot meet at a point, they appears to comes from a point and the image formed is virtual.

MaRussiya [10]3 years ago
3 0
<span>A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). The image of an object is found to be upright and reduced in size.</span>
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Three equal point charges, each with charge 1.15 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
julsineya [31]

Answer:

U=50.96J

Explanation:

The electrostatic potential energy for pair of charge is given by

U=1/4π∈₀×(q₁q₂/r)

Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:

U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)

U=3×1/4π∈₀×(q²/r)

Substitute given values

So

U=3\frac{1}{4\pi E_{o} }\frac{q^{2} }{r}\\  U=3\frac{1}{4\pi8.85*10^{-12} }\frac{(1.15*10^{-6}C )^{2} }{0.0007m}\\  U=50.96J

8 0
3 years ago
if an object is moving with a velocity of 24m/s and has an acceleration of -4m/s how long will it take to stop
ololo11 [35]
The negative sign on the acceleration is only a vector quantity that means the object is accelerating to the left. Hence, we can only focus on it magnitude which is 4 m/s^2. Acceleration is the change in velocity over time. The change in velocity must be 24 m/s - 0 m/s, if you want the object to stop. Therefore,

a = (v2 - v1)/t
4 = (24 - 0)t
t = 6 seconds

The object will stop after 6 seconds.
7 0
3 years ago
On a frictionless surface how much force is necessary to accelerate a 0.49 kg object to the left at 4.8 m/s2?
Alenkasestr [34]

Answer:

<h2>2.35 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

force = 0.49 × 4.8 = 2.352

We have the final answer as

<h3>2.35 N</h3>

Hope this helps you

8 0
2 years ago
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