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alina1380 [7]
4 years ago
13

Why do concave lenses always form virtual images?

Physics
2 answers:
kolbaska11 [484]4 years ago
5 0

Answer:

Explanation:

There are two types of images formed by the lenses or mirrors.

1. Real image: When two refracted or reflected rays actually meet at a point after refraction or reflection, the image formed is real.

2. Virtual image: When two refracted or reflected rays appear to meet at a point after refraction or reflection, the image formed is virtual.

A concave lens is a diverging lens, it means when the rays of light incident on the concave lens, then after refraction, the rays diverges from its original path. Thus, they cannot meet at a point, they appears to comes from a point and the image formed is virtual.

MaRussiya [10]4 years ago
3 0
<span>A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). The image of an object is found to be upright and reduced in size.</span>
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Andrews [41]

Answer:

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4 0
3 years ago
Clois what is the weight of a body in the earth, if its weig is 5Nin moon? <br>​
Debora [2.8K]

Explanation:

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8 0
3 years ago
A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its
Nostrana [21]

Answer:

Its speed is maximum and its acceleration is zero

Explanation:

- Concerning the speed:

In a simple harmonic motion, the speed can be determined through the law of conservation of energy. In fact, we have that the total mechanical energy of the system, which is sum of elastic potential energy U and kinetic energy K, is constant:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2

where k is the spring constant, x is the displacement, m is the mass and v is the speed.

We see that when the displacement is 0, x = 0: this means that the elastic potential energy U is also 0, therefore the kinetic energy K is maximum, and so the speed v is also maximum.

- Concerning the acceleration:

According to Newton's second law, the acceleration of the system is proportional to the net force:

a=\frac{F}{m}

the net force is just the restoring force of the spring, given by Hooke's law:

F=-kx

So, the acceleration is

a=-\frac{kx}{m}

and we see that when the displacement is zero, x = 0, and so the acceleration is also zero.

4 0
4 years ago
For total internal reflection to occur, all of the following must happen but __________. light must travel slower in the first m
bija089 [108]

Answer:

Explanation:

When a ray of light passes through denser medium to rarer medium and then after refraction it comes back into the denser medium, the phenomenon is called total internal refraction.

There are two necessary conditions for the total internal refraction.

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(2) The angle of incidence in the denser medium should be more than the critical angle for that pair of media.

6 0
4 years ago
Read 2 more answers
By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what
Vinil7 [7]

Explanation:

1. Mass of the proton, m_p=1.67\times 10^{-27}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}

V=\dfrac{h^2}{2q_pm_p\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}

V = 45.83 volts

2. Mass of the electron, m_p=9.1\times 10^{-31}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}

V=\dfrac{h^2}{2q_em_e\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}

V=6.92\times 10^{34}\ V

V = 84109.27 volt

Hence, this is the required solution.

7 0
4 years ago
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