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valentinak56 [21]

2 years ago

12

Explain surface tension and capillary action

1 answer:

Andreas93 [3]2 years ago

4 0

Adhesion of water to the surface of a material will cause an upward force on the liquid. The surface tension acts to hold the surface intact. Capillary action occurs when the adhesion to the surface material is stronger than the cohesive forces between the water molecules.

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If a hydrate of the formula

Lelu [443]

Answer:

It will turn red

Explanation:

Bases will turn the litmus paper (impregnated with an acid-base indicator) blue.

Acids will turn turn the litmus paper (impregnated with an acid-base indicator) red.

Since the produced HCl is a strong acid, the litmus paper will turn red, when touching the HCl.

The red shows the presence of an acid, in this case HCl.

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3 years ago

Acetic acid, CH3CO2HCH3CO2H, is the main organic constituent of vinegar. Draw an electron-dot structure for acetic acid. (The tw

malfutka [58]

Answer: acetic acid structure

Explanation:

In the lewis structure we have 24 valence electrons

7 0

2 years ago

What is a proper adjective?

Alex17521 [72]

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7 0

2 years ago

Help pleas I dont understand

Temka [501]

The *independent* variable is the one that you always can control. However, the dependent variables are not since they **depend** on another.

4 0

3 years ago

Read 2 more answers

You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out

mina [271]

Answer:

The diameter of the oil molecule is $4.4674\times 10^{-8} cm$ .

Explanation:

Mass of the oil drop = $m=9.00\times 10^{-7} kg$

Density of the oil drop = $d=918 kg/m^3$

Volume of the oil drop: v

$d=\frac{m}{v}$

$v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}$

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = $4\pi r^2$

$a=4\times 3.14\times (0.418 m)^2=2.1945 m^2$

Volume of the oil drop = v = Area × thickness

$\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x$

$x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm$

The thickness of the oil drop is $4.4674\times 10^{-8} cm$ and so is the diameter of the molecule.

6 0

2 years ago