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4 years ago

During an experiment water was heated in a container covered with a glass lid. The following observations were recorded.

Chemistry

2 answers:

Hatshy [7]4 years ago

7 0

physical, even though it is boiling but the droplets is still water, water when boil was still water

Hitman42 [59]4 years ago

6 0

It is a physical change because it only changed states

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In the unbalanced equation given below, what is the element that is gaining electrons?

viktelen [127]

Hey there!:

HCl + MnO2 → MnCl2 + H2O + Cl2

* in HCl the oxidation state of Cl is -1 .

* on the product side the oxidation state is 0 .

* therefore Cl gains electrons .

* in MnO2 the oxidation state of Mn is +4

* in MnCl2 the oxidation state of Mn is +2

Therefore Mn loses electrons

Answer A

Hope That helps!

4 0

3 years ago

Read 2 more answers

A chemist forms 16.6 g of potassium iodide by combining 3.9 g of potassium with 12.7 g of iodine. Show that these results are co

bezimeni [28]

3.9 g + 12.7 g = 16.6 g

The sum of the masses of potassium and iodine equals the mass of the product, potassium iodide. The results are consistent with he law of conservation of mass.

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3 0

3 years ago

11. The electron configuration for phosphorous is [Ar]3s23p4. TRUE FALSE

user100 [1]

Answer:

False

Explanation:

Phosphorus is number 15 on the periodic table, so its electronic configuration is:

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{3}$

5 0

2 years ago

If 50.0 g of water saturated with potassium chloride at 80.0°C is slowly evaporator to dryness, how many grams of the dry salt w

balu736 [363]

Answer:

25.0 g.

Explanation:

From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.

So, a saturated solution of KCl in 50.0 g of water will contain about 25.0 g.

Thus, the grams of the dry salt that will be recovered is 25.0 g.

5 0

3 years ago

Why is photosynthesis important to the ecosystem everywhere

topjm [15]

It creates oxygen which every living thing needs to live. i hope this helps! :)

7 0

3 years ago