it would be b hope i helped
Answer:
The volume will not change. This belongs in Ripley's Believe It or Not.
Explanation:
The combined gas law can be used to model both the initial (1) and ending (2) states of a gas when pressure (P), temperature (T) and/or volume (V) change, but the number of moles does not. Remember that temperature must always be in Kelvin.
P1V1/T1 = P2T2/T2
Rearranging for V2:
V2 = V1(T2/T1)(P1/P2)
I've arranged the pressure and temperature terms as ratios. This makes it easier to see what impact changes will have, plus the units conveniently cancel for both.
(V2) = (1 L)(T2/T1)(P1/P2)
We are told that P2 and T2 are both doubled:
(T2/T1) = 2
(P1/P2) = 1/2
V2 = (1 L)(T2/T1)(P1/P2)
V2 = (1 L)(2)(1/2)
V2 = (1 L)(2)(1/2)
V2 - 1 L
The volume does not change. Bummer.
Answer:
Explanation:
Hello.
In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:
Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:
Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:
Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:
Best regards.
BY CHECKING THE REACTIVITY OF AN ELEMENT WHICH IS MOST REACTIVE OR NOT AND YOU STUDY TYPE OF CHEMICAL REACTION IN 1 CH AND YOU CHECK THE REACTIVITY OF ELEMENTS IN 3 CH METALS AND NON METALS PAGE NO 45 IN NCERT BOOK
