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vladimir1956 [14]
3 years ago
11

Question 4

Physics
1 answer:
fgiga [73]3 years ago
4 0
Question 4:
some of the energy is being used to change the state of some of the water.

At some places in the pot, usually at the bottom right next to the fire, water
at 100°C is changing to steam at 100°C.  That "phase change" takes energy,
and the temperature doesn't change.

Question 5:
I have no questions about this. I understand it well enough for the time being.
I am confused by many things, but a pot of boiling water is not one of them.
I have no important feedback at this time, but please check back with me
in a week or two. 
Thank you. 

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how much gravitational potential energy do you give a 70 kg person when you lift him up 3 m in the air?
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Given gravitational potential energy when he's lifted is 2058 J.

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velocity of person = 7.67 m/s².

<h3>Explanation:</h3>

Given:

Weight of person = 70 kg

Lifted height = 3 m

1. Gravitational potential energy of a lifted person is equal to the work done.

PE_g=W=m\times g\times h\\Acceleration due to gravity = g = 9.8 \ m/s^2 \\PE_g= m = m\times g\times h= 70\times 9.8 \times 3 = 2058\ kg.m/s^2 = 2058\ J

Gravitational potential energy is equal to 2058 Joules.

2. The Gravitational potential energy is converted into kinetic energy. Kinetic energy is being transferred to the person.

3. Kinetic energy gained = Potential energy lost = -PE_g = -2058\ kg.m/s^2

Kinetic energy gained by the person = (-2058 kg.m/s²)

4. Velocity = ?

Kinetic energy magnitude= \frac{1}{2} m\times v^2 = m\times g \times h

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v=\sqrt{2gh} =\sqrt{2\times 9.8 \times 3} = \sqrt{58.8} = 7.67 m/s^2

The person will be going at a speed of 7.67 m/s².

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