Question

a car accelerates from rest at 3 m / s^2 along a straight road. how far has the car travelled after 4 s

Answer 1

Answer:

24 m

Explanation:

The motion of the car is a uniformly accelerated motion (=at constant acceleration), therefore we  can find the distance covered by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered

u is the initial velocity

t is the time elapsed

a is the acceleration

For the car in this problem:

u = 0, since the car starts from rest

$a=3 m/s^2$ is the acceleration

t = 4 s is the time elapsed

Therefore, the distance covered is:

$s=0+\frac{1}{2}(3)(4)^2=24 m$