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Allisa [31]
4 years ago
7

a 700k/g race car slowed down from 30m/s to 15m/s what is the impulse and what was the average force applied by the brakes

Physics
1 answer:
posledela4 years ago
5 0
So impulse is a change in momentum.

Mass*(final velocity - initial velocity)

I dont think you will be able to find the average force with the given info because you need to know the time it takes for the car to slow down.
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12)A black body is heated from 27°C to 127° C. The ratio of their energies of radiations emitted will be
Nat2105 [25]

Answer:

81:256.

Explanation:

Let T denote the absolute temperature of this object.

Calculate the value of T before and after heating:

T(\text{before}) = 27 + 273 = 300\; \rm K.

T(\text{after}) = 127 + 273 = 400\; \rm K.

By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to T^4.

Ratio between the absolute temperature of this object before and after heating:

\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}.

Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:

\displaystyle \left(\frac{T(\text{before})}{T(\text{after})}\right)^{4} = \left(\frac{3}{4}\right)^{4} = \frac{81}{256}.

4 0
3 years ago
A mercury thermometer is used to measure the temperature of boiling water but why do you think the mountainous travel to cold re
melamori03 [73]

Because mercury freeze in cold temperatures

7 0
3 years ago
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krek1111 [17]

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Explanation:

6 0
3 years ago
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You apply a force of 18 N to a dresser and move it 3.0 m. How much work did you do on the dresser?
charle [14.2K]

Answer:

54 J

Explanation:

Work done = force * displacement

                  = 18 *3

                  = 54 J

7 0
4 years ago
Inside a television picture tube there is a build-up of electrons (charge of 1. 602 × 10–19 C) with an average spacing of 38. 0
Olin [163]

The magnitude of the electric field inside the picture tube is 998.476 kN/C.

<h3>What is an electric field?</h3>

It is an area in the space where a charged particle experiences a force. It can be calculated by the formula,

E =\dfrac {kQ}{r^2 }

Where,

E = electric field produced

Q = charge =  1.602 \times  10^{-19}\rm \  C

r = distance = 38 \times  10^{-9}\rm \  m

k = Coulomb's constant = 9 \times 10^9 \rm \ N. m2 / C2

Put the values in the formula,

E = \dfrac {9 \times 10^9\times 1.602 \times  10^{-19}}{(38 \times  10^{-9})^2}\\\\E = 998.476 \rm \ kN/C

Therefore, the magnitude of the electric field inside the picture tube is 998.476 kN/C.

Learn more about the electric field:

brainly.com/question/3783640

8 0
2 years ago
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