A person watches an ambulance drive by them while emitting a steady sound from its siren. When the ambulance passes the person (
1 answer:
Answer:
21.7 m/s
Explanation:
Let the velocity of ambulance is v and f is the real frequency of siren of ambulance.
the velocity of sound is 343 m/s
use the formula of Doppler's effect
.... (1)
where, f' is the frequency of at the first time.
Now the source is moving away from the person, the frequency is given by
.... (2)
According to the question,
f'' = f' - 11.0 % of f'
f'' = 0.881 f'
By equation (1) and (2)
40.817 = 1.881 v
v = 21.7 m/s
Thus, the speed of ambulance is 21.7 m/s.
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Answer:
a) v₀ = 32.64 m / s , b) x = 59.68 m
Explanation:
a) This is a projectile launching exercise, we the distance and height of the cliff
x = v₀ₓ t
y = t - ½ g t²
We look for the components of speed with trigonometry
sin 43 = v_{oy} / v₀
cos 43 = v₀ₓ / v₀
v_{oy} = v₀ sin 43
v₀ₓ = v₀ cos 43
Let's look for time in the first equation and substitute in the second
t = x / v₀ cos 43
y = v₀ sin 43 (x / v₀ cos 43) - ½ g (x / v₀ cos 43)²
y = x tan 43 - ½ g x² / v₀² cos² 43
1 / v₀² = (x tan 43 - y) 2 cos² 43 / g x²
v₀² = g x² / [(x tan 43 –y) 2 cos² 43]
Let's calculate
v₀² = 9.8 60 2 / [(60 tan 43 - 25) 2 cos 43]
v₀ = √ (35280 / 33.11)
v₀ = 32.64 m / s
.b) we use the vertical distance equation with the speed found
y = t - ½ g t²
.y = v₀ sin43 t - ½ g t²
25 = 32.64 sin 43 t - ½ 9.8 t²
4.9 t² - 22.26 t + 25 = 0
t² - 4.54 t + 5.10 = 0
We solve the second degree equation
t = (4.54 ±√(4.54 2 - 4 5.1)) / 2
t = (4.54 ± 0.46) / 2
t₁ = 2.50 s
t₂ = 2.04 s
The shortest time is when the cliff passes and the longest when it reaches the floor, with this time we look for the horizontal distance traveled
x = v₀ₓ t
x = v₀ cos 43 t
x = 32.64 cos 43 2.50
x = 59.68 m
Answer:
The value is
Explanation:
From the question we are told
The pipe diameter at location 1 is
The velocity at location 1 is
The diameter at location 2 is
Generally the area at location 1 is
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Generally the area at location 1 is
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Generally from continuity equation we have that
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